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3 years ago

Covert 110% to a decimal

Mathematics

1 answer:

omeli [17]3 years ago

5 0

That would be 1.1 in decimals.

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Find the missing angle

eimsori [14]

Answer:

50 degrees

Step-by-step explanation:

Right Angle= 90 degrees

90-40=50

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3 years ago

Anyone know the value of x I’m horrible at geo

Dima020 [189]

5 will be your answer of this question

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3 years ago

what is "The temperature outside at 6 a.m. is 4 degrees celsius. The temperature rising by 1.5 degrees celsius every hour." in a

LiRa [457]

Answer:

7 a.m is 5.5

Step-by-step explanation:

(6=4)+1.5=(_+1.5)

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3 years ago

You are given that <GHJ is a complement of <RST and <RST is a supplement of <ABC. Let m<GHJ be x°. What is the me

MAVERICK [17]

∠GHJ and ∠RST are complementary

⇒ ∠GHJ and ∠RST = 90°

And ∠RST and ∠ABC are supplementary

⇒ ∠RST and ∠ABC = 180°

Also, ∠GHJ = x°

⇒ ∠RST = 90° - x°

⇒ ∠ABC = 180° - ∠RST

⇒ ∠ABC = 180° - (90° - x°)

⇒ ∠ABC = 90° + x°

6 0

3 years ago

A rectangular storage container with a lid is to have a volume of 2 m3. The length of its base is twice the width. Material for

Scilla [17]

Answer:

Dimensions are 2 m by 1 meter by 1 meter,

Minimum cost is $ 18.

Step-by-step explanation:

Let w be the width ( in meters ) of the container,

Since, the length is twice of the width,

So, length of the container = 2w,

Now, if h be the height of the container,

Volume = length × width × height

2 = 2w × w × h

1 = w² × h

$\implies h=\frac{1}{w^2}$

Since, the area of the base = l × w = 2w × w = 2w²,

Area of the lid = l × w = 2w²,

While the area of the sides = 2hw + 2hl

= 2h( w + l)

$= 2\times \frac{1}{w^2}(w+2w)$

$=\frac{6w}{w^2}$

$=\frac{6}{w}$

Since, Material for the base costs $1 per m². Material for the sides and lid costs $2 per m²,

So, the total cost,

$C(w) = 1\times 2w^2+2\times 2w^2 + 2\times \frac{6}{w}$

$=2w^2+4w^2+\frac{12}{w}$

$=6w^2+\frac{12}{w}$

Differentiating with respect to w,

$C'(w) = 12w -\frac{12}{w^2}$

Again differentiating with respect to w,

$C''(w) = 12 + \frac{24}{w^3}$

For maxima or minima,

C'(w) = 0

$\implies 12w -\frac{12}{w^2}=0$

$\implies 12w^3 - 12=0$

$w^3-1=0\implies w = 1$

For w = 1, C''(w) = positive,

Hence, for width 1 m the cost is minimum,

Therefore, the minimum cost is C(1) = 6(1)²+12 = $ 18,

And, the dimension for which the cost is minimum is,

2 m by 1 meter by 1 meter.

7 0

3 years ago