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arsen [322]
4 years ago
9

Hey I need these by 8am or I'm screwed,

Mathematics
1 answer:
tiny-mole [99]4 years ago
5 0
34.4 / 4 = 8.6 

The value 214.01 is greater.

2.5 x 10^3 = 2,500

1 M = 100 CM
2 M = 200 CM
3 M = 300 CM
4 M = 400 CM
5 M = 500 CM
6 M = 600 CM
7 M = 700 CM

If you want detailed explanations after you get done with your classes ill be glad to explain. Happy studying!

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I will mark you brainliest if its correctly
zheka24 [161]

Step-by-step explanation:

sina = -√3/2

\cos(a)  =   \sqrt{1 -  { \sin(a) }^{2} }

=  \sqrt{1 -  { (\frac{  - \sqrt{ 3} }{2}) }^{2} }

=  \sqrt{ \frac{4 - 3}{4} }

=  \sqrt{ \frac{1}{4} }

=±1/2

Since, π<a<3π/2

cos a = -1/2

\tan(a )=  \frac{ \sin(a) }{ \cos(a) }

\tan(a )  =  \sqrt{3}

OptionB

8 0
3 years ago
How many solutions are there to the equation 4(x-5)=3x+7
stich3 [128]

Answer:

x=27

Step-by-step explanation:

Let's solve your equation step-by-step.

4(x−5)=3x+7

Step 1: Simplify both sides of the equation.

4(x−5)=3x+7

(4)(x)+(4)(−5)=3x+7(Distribute)

4x+−20=3x+7

4x−20=3x+7

Step 2: Subtract 3x from both sides.

4x−20−3x=3x+7−3x

x−20=7

Step 3: Add 20 to both sides.

x−20+20=7+20

x=27

Answer:

x=27

6 0
3 years ago
Read 2 more answers
What are the steps to divide 36.75 by 3?
Nadya [2.5K]

Answer:

12.25

Step-by-step explanation:

(1): "36.75" was replaced by "(3675/100)".

2 Simplify 147/4

3 147 /4 divided by 3

.....

49/4 which equal 12.25000

5 0
3 years ago
The publisher of a recently released nonfiction book expects that over the first 20 months after its release, the monthly profit
wolverine [178]

Answer:

(a)\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

(b)P'(5)=-($4.54) Thousand

(c)P'(11)=-($2.10) Thousand

(d)The fifth Month

Step-by-step explanation:

Given the monthly profit model:

P(t)=\frac{240t-40t^2}{t^2+20}

(a)We want to derive a model that gives the Marginal Profit, P' of the book.

We differentiate

P(t)=\frac{240t-40t^2}{t^2+20} using quotient rule.

\frac{dP}{dt}=\frac{(t^2+20)(240-80t)-(240t-40t^2)(2t)}{(t^2+20)^2}

Simplifying

\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

We have derived a model for the marginal profit.

(b) After 5 months, at t=5

Marginal Profit=P'(5)

\frac{dP}{dt}=\frac{4800-1600t-240t^2}{(t^2+20)^2}

P^{'}(5)=\frac{4800-1600(5)-240(5)^2}{(5^2+20)^2}

=-($4.54) Thousand of dollars

(c)Marginal Profit 11 Months after book release

P^{'}(11)=\frac{4800-1600(11)-240(11)^2}{(11^2+20)^2}

=-($2.10) Thousand of dollars

(d) Since the marginal profit at t=5 is negative, after the 5th Month, the profit starts to experience a steady decrease.

6 0
3 years ago
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo
muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: {\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}

Where \lambda is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}

Substitute the respective values in the above formula.

P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})

P(k > 2)= 1 - (0.44596)

P(k > 2)=0.55404

Hence, the required probability is 0.55404.

4 0
3 years ago
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