If I'm understanding this correctly 20 rounded to the nearest ten would be 20
Given:
The initial mass of an element is 800 grams.
Decay rate = 8.2% per day
Number of days = 15
To find:
The remaining element after 15 days.
Solution:
The exponential decay model is

Where, a is the initial value r is the rate of interest and t is time period.
Putting
in the above formula, we get




Therefore, the mass of the remaining element is 221.7 grams.
A. the coordinates for the 3rd one is (7, -4)
Answer: Two and one tenth.
Answer: Each bow needs 4.67 yards of ribbon.
Step-by-step explanation:
We know that each roll has 20 yd.
She used 3 + 1/2 rolls, then the total length used will be (3 + 1/2) times the length of each roll, this is:
(3 + 1/2)*20 yd = (6/2 + 1/2)*20yd = (7/2)*20yd = 70 yd.
With tose 70 yards of ribbon, she made 15 bows, then the length of ribbon used in each bow will be equal to the quotient between the total length used and the number of ribbons made with it, this is:
70yd/15 = 4.67 yards
Each bow needs 4.67 yards of ribbon.