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3 years ago

Brenda collected this data from an experiment.

Mathematics

2 answers:

Gelneren [198K]3 years ago

8 0

Answer:

7.04

Step-by-step explanation:

To get the value of residual of the data point, we simply substitute 11 for t

The substitution equation is h = 0.6t + 0.44

Substituting 11, we have

h = 0.6(11) + 0.44

h = 6.6 + 0.44

h = 7.04

Grace [21]3 years ago

6 0

Answer:

The residual of the data point h = 0.6t + 0.44, is h = 7.04.

Step-by-step explanation:

Given the line of fit, h = 0.6t + 0.44, which Brenda collected from an experiment, at the point t = 11, the residual of the data point is obtained by replacing t with 11 in the given equation h = 0.6t + 0.44.

Doing this, we have

h = 0.6(11) + 0.44

h = 6.6 + 0.44

= 7.04

This is what we want to obtain.

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A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 335335 babies were born

strojnjashka [21]

Answer:

The 99% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

Step-by-step explanation:

Confidence Interval for the proportion:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 335, \pi = \frac{268}{335} = 0.8$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.7437$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.8563$

For the percentage:

Multiplying the proportions by 100.

The 99% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

7 0

3 years ago

Simply the following expression: 8x + 5y - 4z + 9y - 3x + 13z

oksian1 [2.3K]

Answer:

5x+14y+9z

Step-by-step explanation:

combine 8x and -3x to get 5x

combine 5y and 9y to get 13y

combine -4z and 13z to get 9z

7 0

3 years ago