Use linear Approximation to approximate e^.01
1 answer:
<span>Suppose that:
let f(x) = e^x
Suppose:
a = 0
</span>Now we are finding <span>f(a):</span><span>
f(a) = f(0) = 1
f '(x) = e^x
Now we are finding </span>f '(a):<span>
f '(a) = f '(0) = 1
Putting the formula:
L(x) = f(a) + f '(a)( x - a)
L(e^0.01) = 1 + 1(0.01 - 0)
= 1.01 is the answer</span>
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