Hope this helps.................
Answer:
![\begin{bmatrix}\mathrm{Solution:}\:&\:x\le \frac{1200}{499}\:\\ \:\mathrm{Decimal:}&\:x\le \:2.40480\dots \\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:\frac{1200}{499}]\end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D%5Cmathrm%7BSolution%3A%7D%5C%3A%26%5C%3Ax%5Cle%20%5Cfrac%7B1200%7D%7B499%7D%5C%3A%5C%5C%20%5C%3A%5Cmathrm%7BDecimal%3A%7D%26%5C%3Ax%5Cle%20%5C%3A2.40480%5Cdots%20%5C%5C%20%5C%3A%5Cmathrm%7BInterval%5C%3ANotation%3A%7D%26%5C%3A%28-%5Cinfty%20%5C%3A%2C%5C%3A%5Cfrac%7B1200%7D%7B499%7D%5D%5Cend%7Bbmatrix%7D)
Step-by-step explanation:

Answer:
x=y^2-2
Step-by-step explanation:
This graph, is a parabola that opens to the right.
To answer this question, we just use the vertex form of a sideways parabola- x=a(y-k)^2+h.
In this case, the vertex is (-2, 0), and our value of a is 1, since it opens to the right.
This gives us: x=1(y-0)^2+(-2)
Which simplifies to: x=y^2-2.
Also, the answer to the previous two questions are wrong.
The D value (Domain) is actually [2, ∞)
The R value (Range) is actually "All real numbers" (-∞, ∞)
Let me know if this helps!
Answer:
the answer is below
Step-by-step explanation:
We have the total number of possible samples = 4 * 4 = 16 (As 4 choices for each value)
in addition we have to as all sample occur with equal probability, probability of each sample = 1/16, below is samling distribution of mean
x1 x2 probabilityP(x1,x2) sample mean
190 190 1/16 190
190 100 1/16 145
190 272 1/16 231
190 74 1/16 132
100 190 1/16 145
100 100 1/16 100
100 272 1/16 186
100 74 1/16 87
272 190 1/16 231
272 100 1/16 186
272 272 1/16 272
272 74 1/16 173
74 190 1/16 132
74 100 1/16 87
74 272 1/16 173
74 74 1/16 74
Summarizing above with adding duplicate values
sample mean probability
74 1/16
87 1/8
100 1/16
132 1/8
145 1/8
173 1/8
186 1/8
190 1/16
231 1/8
272 1/16