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dmitriy555 [2]
3 years ago
5

jacks car used 18 gallons of gasoline to go 468 miles. At that rate, how many gallons would be used to go 754 miles? Explain you

r answer
Mathematics
2 answers:
matrenka [14]3 years ago
6 0
Well if you take 468 and divide it by 18 you get 26 that 26mpg take 754 divide it by 26 and you get 29 and that's how many gallons he used
TiliK225 [7]3 years ago
5 0

Answer:

29 gallons

Step-by-step explanation:

Jacks car used 18 gallons of gasoline to go 468 miles.

we have to calculate the amount of gasoline would be used to go 754 miles.

∵ 18 gallons of gasoline were used to travel = 468 miles

∴ 1 gallon of gasoline were used to travel = \frac{468}{18}

                                                                                       = 26 miles

∴ to cover the distance of 754 miles gasoline would be used = \frac{754}{26}

                     = 29 gallons of gasoline

29 gallons of gasoline would be used to go 754 miles.

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Can someone help me question 17? Pls I really need how I can solve this question???
Anit [1.1K]
You can use the distance formula: d = sqrt((second x value - first x value)^2 + (second y value - first y value)^2):
answer : d = sqrt((3+2)^2+(6+6)^2) = 11.95826074 units
4 0
3 years ago
A rock thrown vertically upward from the surface of the moon at a velocity of 36​m/sec reaches a height of s = 36t - 0.8 t^2 met
Verdich [7]

Answer:

a. The rock's velocity is v(t)=36-1.6t \:{(m/s)}  and the acceleration is a(t)=-1.6  \:{(m/s^2)}

b. It takes 22.5 seconds to reach the highest point.

c. The rock goes up to 405 m.

d. It reach half its maximum height when time is 6.59 s or 38.41 s.

e. The rock is aloft for 45 seconds.

Step-by-step explanation:

  • Velocity is defined as the rate of change of position or the rate of displacement. v(t)=\frac{ds}{dt}
  • Acceleration is defined as the rate of change of velocity. a(t)=\frac{dv}{dt}

a.

The rock's velocity is the derivative of the height function s(t) = 36t - 0.8 t^2

v(t)=\frac{d}{dt}(36t - 0.8 t^2) \\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\v(t)=\frac{d}{dt}\left(36t\right)-\frac{d}{dt}\left(0.8t^2\right)\\\\v(t)=36-1.6t

The rock's acceleration is the derivative of the velocity function v(t)=36-1.6t

a(t)=\frac{d}{dt}(36-1.6t)\\\\a(t)=-1.6

b. The rock will reach its highest point when the velocity becomes zero.

v(t)=36-1.6t=0\\36\cdot \:10-1.6t\cdot \:10=0\cdot \:10\\360-16t=0\\360-16t-360=0-360\\-16t=-360\\t=\frac{45}{2}=22.5

It takes 22.5 seconds to reach the highest point.

c. The rock reach its highest point when t = 22.5 s

Thus

s(22.5) = 36(22.5) - 0.8 (22.5)^2\\s(22.5) =405

So the rock goes up to 405 m.

d. The maximum height is 405 m. So the half of its maximum height = \frac{405}{2} =202.5 \:m

To find the time it reach half its maximum height, we need to solve

36t - 0.8 t^2=202.5\\36t\cdot \:10-0.8t^2\cdot \:10=202.5\cdot \:10\\360t-8t^2=2025\\360t-8t^2-2025=2025-2025\\-8t^2+360t-2025=0

For a quadratic equation of the form ax^2+bx+c=0 the solutions are

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-8,\:b=360,\:c=-2025:\\\\t=\frac{-360+\sqrt{360^2-4\left(-8\right)\left(-2025\right)}}{2\left(-8\right)}=\frac{45\left(2-\sqrt{2}\right)}{4}\approx 6.59\\\\t=\frac{-360-\sqrt{360^2-4\left(-8\right)\left(-2025\right)}}{2\left(-8\right)}=\frac{45\left(2+\sqrt{2}\right)}{4}\approx 38.41

It reach half its maximum height when time is 6.59 s or 38.41 s.

e. It is aloft until s(t) = 0 again

36t - 0.8 t^2=0\\\\\mathrm{Factor\:}36t-0.8t^2\rightarrow -t\left(0.8t-36\right)\\\\\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}\\\\t=0,\:t=45

The rock is aloft for 45 seconds.

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3 years ago
the temperature ,t, in Burrtown starts at 21 degrees F at midnight, when h=0. For the next few hours, the temperature drops 4 de
lbvjy [14]

the temperature ,t, in Burrtown starts at 21 degrees F at midnight, when h=0. For the next few hours, the temperature drops 4 degrees every hour. which equation represents the temperature ,t, at hour h?

t =21-4h


7 0
3 years ago
What is the value of x?
grandymaker [24]

i got 5.14cm i don´t know how much you are supposed to round though

36/42= 0.857142857 x 6=5.142857143

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3 years ago
Which of the following rational functions is graphed below?
Radda [10]
The answer is B, f(x)=1/(x-6)
3 0
2 years ago
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