Answer:
it's 6n + 7
Step-by-step explanation:
hope this helped a little bit :))
The area of the wetland that will be covered in purple loosestrife 7 years from now is modeled by this expression.
500(1.2)^7
After evaluating the expression, the model predicts that approximately 1,792 acres of the wetland will be covered in purple loosestrife 7 years from now. This is not a valid prediction because the total area of the wetland is only 1,240 acres. So a constraint on the model is that the value of the expression 500(1.2)^t must be less than or equal to 1,240.
The question is asking to states the value of the z-score of a value that is 2.08 standard deviations greater than the mean and base on my research, the possible answer would be z-score is the number of standard deviations above the mean. <span>If you are 5 standard deviations above the mean, that is defined as z = 5. </span><span>If you are 1.1 standard deviations above the mean, that is defined as z = 1.1. </span>
<span>And so if you are 2.08 standard deviations above the mean</span>
Answer:
Please check the explanation.
Step-by-step explanation:
Given the decimal number

Rewrite as

∵ 0.05 = 5/100



Given the decimal number
12.346
Rewrite as

∵ 0.346 = 346/1000 = 173/500

Given the decimal number
7.5
Rewrite as

∵ 0.5 = 1/2

Answer:
A task time of 177.125s qualify individuals for such training.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.
In this problem, we have that:
A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so
.
The fastest 10% are to be given advanced training. What task times qualify individuals for such training?
This is the value of X when Z has a pvalue of 0.90.
Z has a pvalue of 0.90 when it is between 1.28 and 1.29. So we want to find X when
.
So




A task time of 177.125s qualify individuals for such training.