6+1m= t. That’s the equation for the problem.
A1=2
a2=-8
a3=32
a4=-128
a2/a1=(-8)/2→a2/a1=-4
a3/a2=32/(-8)→a3/a2=-4
a4/a3=(-128)/32→a4/a3=-4
a2/a1=a3/a2=a4/a3=r=-4
an=a1*r^(n-1)
an=2*(-4)^(n-1)
The explicit rule for the nth term of the given sequence is an=2*(-4)^(n-1)
Answer: x = 2921, y = 579
Step-by-Step Explanation:
I am assuming that we just have to Solve for ‘x’ and ‘y’.
‘x’ = No. Of Contemporary Titles
‘y’ = No. Of Classic Titles
=> x + y = 3500 (Eq. 1)
=> x - y = 2342 (Eq. 2)
Adding Eq. 1 and Eq. 2, we get :-
2x = 3500 + 2342
2x = 5842
x = 5842/2
=> x = 2921
Therefore, x = 2921
Substitute value of ‘x’ in Eq. 1 :-
x + y = 3500
(2921) + y = 3500
y = 3500 - 2921
=> y = 579
Therefore, y = 579
Hence,
No. Of Contemporary Titles = 2921
No. Of Classic Titles = 579
