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NikAS [45]
2 years ago
13

Homework . a A man bought for GH¢ 5,500 and sold it for GH & 6,500. Find the Percentage gain.​

Mathematics
1 answer:
vodka [1.7K]2 years ago
4 0

Answer:

18%

Step-by-step explanation:

5500y=6500

y=6500/5500

y=1.18

1.18*100=118%

118%-100%=18%

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A bag contains 2 red marbles, 4 blue marbles and 8 green marbles. If two marbles are drawn out of the bag, what is the probabili
Hoochie [10]

Answer:

0.1

Step-by-step explanation:

total number of marbles= 2+4+8=14 marbles

probability of getting 2blue

= 4/14×3/13= 4×3/14×13=12/182= 0.06593

to the nearest tenth= 0.1

5 0
2 years ago
19. Given m29 = 2x + 3, m27 = 3x – 9, and m/1 = x + 18, ,<br> what is the value of x?
Crank

Answer:

15

Step-by-step explanation:

jk

8 0
3 years ago
38 = y/2. <br> What equals y?
yan [13]
<span>38 = y/2.
y = 38 * 2
y  = 76

answer
y = 76</span>
5 0
3 years ago
Read 2 more answers
What is the future value of $1,600 in 17 years assuming an interest rate of 10 percent compounded semiannually?
Naddika [18.5K]
Let
F--------------------> future value
P--------------------> present value 
r --------------------> interest rate per year
m ------------------ > number of compounding periods per year
t -------------------->  time in years. 
we know that
P=$1,600
<span>t=17 years
m=2
r=10%------> 0.10

F=P(1+i)</span><span>^n
</span><span>where
i=r/m   ---------> 0.10/2=0.05
and
n=m*t------------> 2*17=34

</span>F=1600*(1+0.05)^34=8405.36
<span>
the answer is $</span>8405.36<span>

</span>
5 0
2 years ago
A triangle has side lengths of 9 in, 13 in, and 20 in. What is the measurement of this triangle’s largest angle?
zvonat [6]
1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :

      i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.

       ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:

       a^{2}=b ^{2}+c ^{2}-2bc(cosA)

2. 

20^{2}=9 ^{2}+13 ^{2}-2*9*13(cosA)&#10;&#10;400=81+169-234(cosA)   150=-234(cosA)&#10;&#10;cosA=150/-234= -0.641

3. m(A) = Arccos(-0.641)≈130°, 

4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
4 0
3 years ago
Read 2 more answers
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