6x
42/6 = 7 (valid), 18/6 = 3 (valid), 12/6 = 2 (valid)
7, 8, 9, 10, and 11 are all not divisible by 12, and 12 is not divisible by 18, so 6 is the highest number.
Also, each number has at least one x, so you can take one out.
Remaining=
6x (7 + 3x^2 + 2x^3)
Answer:
The -7 changes to 7 and the ordered pair of the new point is (4,7)
The -2 changes to 2 and the ordered pair of the new point is (2,-5)
Step-by-step explanation:
Hope this helped.
To solve this problem you must apply the proccedure shown below:
1. You have:
<span>
In(2x+3)=7
2. Then, you must apply log(e), as below:
</span><span>
In(2x+3)=ln(e^7)
3. Now, you obtain:
2x+3=e^7
4. Youy must clear the variable "x", as below:
2x=e^7-3
</span> x=(e^7-3)/2
<span>
5. Therefore, the value of "x" is:
x=546.817
</span><span>
The answer is: </span>x=546.817<span> </span>
