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Nataly [62]
3 years ago
8

Find dy/dx y = 5/8x^3/7 + 8x^4 + 6x - 9

Mathematics
1 answer:
aleksandrvk [35]3 years ago
5 0

Answer:

15/56x^(-4/7) + 32x^3 + 6.

Step-by-step explanation:

Using  the rule for algebraic differentiation:

If  y = ax^n, dy/dx = anx^(n-1).

So :

If  y = 5/8x^3/7 + 8x^4 + 6x - 9

dy/dx = 5/8* 3/7 x^(3/7-1) + 8*4 x^(4-1) + 6x(1-1)

=  15/56x^(-4/7) + 32x^3 + 6.

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You have to do 7,800 divide by 12 and you get D) 650.

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A Spanish teacher informed her class that she would be giving 4 quizzes each month. Write an equation that shows the relationshi
Free_Kalibri [48]

Answer:

y = 4x

Step-by-step explanation:

Since there are going to be four quizzes a month (x), we know that we will multiply the number of months (x) by the number of quizzes (4). However, because we don't know how many months there are, we can define the months as (x), and instead put the total (y) is equal to the number of quizzes per month (4), multiplied by the number of months (x). Out final result is

(y = 4x)

6 0
2 years ago
Another name for an if-then statement is a ____. Every conditional has two parts. The part following if is the ____ , and the pa
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1. 
C) conditional; hypothesis; conclusion.
2. 
A) If a triangle has three sides, than all triangles have three sides.
4 0
3 years ago
Read 2 more answers
A business executive bought 40 stamps for
alekssr [168]

Answer:

32 33-cent stamps, 8 23-cent stamps

Step-by-step explanation:

In order to solve this question, we need to set up a system of equations. Also known as solving for two variables (the number of each stamp).

Let's set x to be the number of 33-cent stamps. Similarly, let's set y to be the number of 23-cent stamps.

To make our first equation, let's think about the number of stamps total we have. We can say:

x + y =40

<em>(AKA - The number of 33-cent stamps, plus the number of 23-cent stamps, equals 40 stamps.)</em>

Now, let's make an equation for the cost of these stamps.

0.33x + 0.23y = 12.40

<em>(AKA - The cost of the stamps in total, should equal $12.40).</em>

So now, we have our two equations:

x + y =40\\0.33x+0.23y=12.40

If you have a TI-84 graphing calculator, you can go to apps -> polysmlt2 -> simultaneous eqn solver, and then input these equations into the menu. This will solve the problem for you.

If you need to do this manually, let's use substitution. Condense our first equation to make it more substitutable.

x+y=40\\x=40-y

Now, let's put this into our second equation.

0.33x+0.23y=12.40\\0.33(40-y)+0.23y=12.40

Distribute, and solve for y.

13.2-0.33y +0.23y =12.40\\13.2-0.1y=12.40\\-0.1y=-0.8\\y=8

Now, we plug this into one of our equations.

x+y=40\\x+8=40\\x=32

In the end, we have thirty-two 33-cent stamps, and eight 23-cent stamps.

3 0
1 year ago
Help me with this please
drek231 [11]
The answer is only C and D
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3 years ago
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