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4 years ago

Find dy/dx y = 5/8x^3/7 + 8x^4 + 6x - 9

Mathematics

1 answer:

aleksandrvk [35]4 years ago

5 0

Answer:

15/56x^(-4/7) + 32x^3 + 6.

Step-by-step explanation:

Using the rule for algebraic differentiation:

If y = ax^n, dy/dx = anx^(n-1).

So :

If y = 5/8x^3/7 + 8x^4 + 6x - 9

dy/dx = 5/8* 3/7 x^(3/7-1) + 8*4 x^(4-1) + 6x(1-1)

= 15/56x^(-4/7) + 32x^3 + 6.

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3 years ago

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Read 2 more answers