First, reorder the numbers for each person.
The median is basically the middle number. If there are 2 middle numbers, then take the average of the two of them.
Pedro: 4, 5, 6, 7, 8, 9
The 2 middle numbers are 6 and 7. The average of 6 and 7 is 6.5 .
Median = 6.5
Alex: 3, 5, 5, 5, 9, 9
The 2 middle numbers are 5 and 5; so basically, the average is 5.
Median = 5
Jaime: 3, 4, 6, 8, 8, 9
The 2 middle numbers are 6 and 8 and thus, the average is 7.
Median = 7
So the answer should be Jaime.
Answer: you alredy solved it
Step-by-step explanation:
Answer:
The slope intercept form is y=-7x+59
Step-by-step explanation:
y-y=m(x-x1)
y-3=-7(x-8)
y-3=-7x+56
+3 +3
y=-7x+59
Answer:
∛V / (4/3π) = r
Step-by-step explanation:
V = 4/3πr³
Try to isolate r if you want to solve for it.
So divide everything that's not r from the right side in order to move it to the left side of the equation.
V / (4/3π) = r³
Then since it is raised to the power of 3 , just cube root the other side in order to undo the exponent. This is so you can isolate r.
∛(V/(4/3π)) = r


the discriminant is a negative value, thus no solution for such quadratic, meaning if we use h=64.5 like we did, there's no "t" seconds at which point the ball hits the batting cage.