Problem 1
We'll use the product rule to say
h(x) = f(x)*g(x)
h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)
Then plug in x = 2 and use the table to fill in the rest
h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)
h ' (2) = f ' (2)*g(2) + f(2)*g ' (2)
h ' (2) = 2*3 + 2*4
h ' (2) = 6 + 8
h ' (2) = 14
<h3>Answer: 14</h3>
============================================================
Problem 2
Now we'll use the quotient rule
<h3>Answer: -2/9</h3>
============================================================
Problem 3
Use the chain rule
<h3>Answer: 12</h3>
Answer:
a= -2 b =4
Step-by-step explanation:
I put it in a calculator and found the answer
Answer:
- sin = -√3/2
- cos = -1/2
- tan = √3
- sec = -2
- csc = (-2/3)√3
- cot = (√3)/3
Step-by-step explanation:
See the attached picture for a drawing of the angle and its terminal point coordinates. Those are (cos(4π/3), sin(4π/3)), so we have the following trig function values:
sin(4π/3) = -√3/2
cos(4π/3) = -1/2
tan(4π/3) = sin/cos = √3
sec(4π/3) = 1/cos = -2
csc(4π/3) = 1/sin = -(2√3)/3
cot(4π/3) = 1/tan = (√3)/3
_____
<em>Additional comment</em>
It helps to know that 1/√a = (√a)/a. This lets you write the ratios with a rational denominator in each case.
Answer:
not sure for the 1st one but pretty sure 2nd one is B
Step-by-step explanation:
