All categories

2 years ago

Help almost done....

Mathematics

1 answer:

zloy xaker [14]2 years ago

4 0

It’s super blurry on my end but B looks like the correct answer

You might be interested in

If you can help with any of these two or both that would be great ! :) thanks

Vladimir [108]

Answer:

hmmm not sure

Step-by-step explanation:

try mulitply the numbers

7 0

2 years ago

Plz help me !!!!!!!!!!!

Artist 52 [7]

Split the second term in 3a^2 - 8a + 4 into two terms

3a^2 - 2a - 6a + 4 = 0

Factor out common terms in the first two terms, then in the last two terms.

a(3a - 2) -2(3a - 2) = 0

Factor out the common term 3a - 2

(3a - 2)(a - 2) = 0

Solve for a;

a = 2/3,2

Answer : B. (2/3,2)

6 0

2 years ago

Very confusing not sure

Arturiano [62]

Answer:

This describes a translation.

8 0

3 years ago

If f(x) = x-6 and g(x)= 1/2x (x+3), find g(x) * f(x)

sertanlavr [38]

Answer:

Final answer is $g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}$ .

Step-by-step explanation:

given functions are $f(x)=x-6$ and $g\left(x\right)=\frac{1}{2x\left(x+3\right)}$ .

Now we need to find about what is the value of $g\left(x\right)*f\left(x\right)$ .

$g\left(x\right)*f\left(x\right)$ simply means we need to multiply the value of $f(x)=x-6$ and $g\left(x\right)=\frac{1}{2x\left(x+3\right)}$ .

$g\left(x\right)\cdot f\left(x\right)=\frac{1}{2x\left(x+3\right)}\cdot\left(x-6\right)$

$g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}$

Hence final answer is $g\left(x\right)\cdot f\left(x\right)=\frac{\left(x-6\right)}{2x\left(x+3\right)}$ .

5 0

2 years ago

11m −4/3=2m+5/3 pls tell me this answer is the answer 3

Oksana_A [137]

Answer:

m=1/3

Step-by-step explanation:

11m- 4/3=2m+5/3

-2m. - 2m

9m -4/3=5/3

+4/3.+ 4/3

9m= 9/3

m=1/3

6 0

2 years ago

Help almost done....​

Help almost done....