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Elena-2011 [213]
3 years ago
6

Please help asap ty !!

Mathematics
2 answers:
Advocard [28]3 years ago
6 0

Answer:

B

Step-by-step explanation:

artcher [175]3 years ago
3 0

Answer:

The Graph located as B.

Step-by-step explanation:

:) Thank you i have done this before! I hope you have a great life?!

Thanks so much! Byes!

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Solve the following....<br> <img src="https://tex.z-dn.net/?f=5x%2B3y%3D7%5C%5C3x-5y%3D-23" id="TexFormula1" title="5x+3y=7\\3x-
AlekseyPX

\qquad\qquad\huge\underline{{\sf Answer}}

let's solve ~

The given equations are :

\qquad \tt \dashrightarrow \:5x + 3y = 7 \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \: \:  - (1)

and

\qquad \tt \dashrightarrow \:3x - 5y = -  23 \:    \:  \:  \:  \: \:  - (2)

Now, let's multiply equation (1) by 5 and equation (2) by 3 ~

we will get the results as :

\qquad \tt \dashrightarrow \:25x + 15y = 35 \:  \:  \:  \:  - (3)

\qquad \tt \dashrightarrow \:9x - 15y  = - 69 \:  \:  \:  - (4)

Now, add equation (3) and (4) :

\qquad \tt \dashrightarrow \:25x + \cancel{ 15y} + 9x -  \cancel{15y }= 35 + ( - 69)

\qquad \tt \dashrightarrow \:34x =  - 34

\qquad \tt \dashrightarrow \:x =  - 1

Now, since we got the value of x, let's evaluate y~ by using equation (1) :

\qquad \tt \dashrightarrow \:5x + 3y = 7

\qquad \tt \dashrightarrow \:5( - 1)+ 3y = 7

\qquad \tt \dashrightarrow \:3y - 5 = 7

\qquad \tt \dashrightarrow \:3y = 12

\qquad \tt \dashrightarrow \:y = 4

Hence, value of y is 4

I hope you understood the whole procedure ~

8 0
2 years ago
Read 2 more answers
What divided by 20equals 12
brilliants [131]
20/12 = 1.6 recurring (that is, 1.6666...)
7 0
3 years ago
What is the square root of 36y16
kotykmax [81]
It is 6y^4 this is the answer
7 0
3 years ago
PLEASE HELP!!!<br>what is the length of segment SR? units​
AlekseyPX

Answer:

x=2

Step-by-step explanation:

2x+8=8x-4

2x+12=8x

12=6x

2=x

x=2

4 0
3 years ago
Chris put $1,500 in a savings account at an annual interest rate of 5%. If Chris does not deposit or withdraw any money, what is
Anon25 [30]

\bf ~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$1500\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ t=years\dotfill &1 \end{cases} \\\\\\ I=(1500)(0.05)(1)\implies I=75

7 0
3 years ago
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