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Elena-2011 [213]
3 years ago
6

Please help asap ty !!

Mathematics
2 answers:
Advocard [28]3 years ago
6 0

Answer:

B

Step-by-step explanation:

artcher [175]3 years ago
3 0

Answer:

The Graph located as B.

Step-by-step explanation:

:) Thank you i have done this before! I hope you have a great life?!

Thanks so much! Byes!

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What point is not included in the solution set for the inequality (0,6) (1,5) (2,4) (3,2) ​
Setler79 [48]

Answer:

(3, 2)

Step-by-step explanation:

To be considered part of a solution set for the inequality provided, a given point must lie within the shaded region that is graphed. Since we want to find the point that is <em>not</em> included in the solution set for the inequality, we need to find the point that does <em>not</em> lie in the shaded region.

Let's test each point to see which doesn't lie in the region. Refer to the image below if you're having trouble graphing the points:

  • (0, 6): This point lies in the shaded region, so it is not our answer.
  • (1, 5): This point lies in the shaded region, so it is not our answer.
  • (2, 4): This point lies in the shaded region, so it is not our answer.
  • <u>(3, 2): This point </u><u><em>does not</em></u><u> lie in the shaded region, so it is our answer.</u>

<u></u>

Hope this helps!

7 0
2 years ago
Find the roots of y= -3^2 - 5x +1
Reil [10]

Answer:

The right answer is the second

Step-by-step explanation:

D=b^2-4ac

D=25+12

D=37

7 0
3 years ago
Evaluate. (4/5)3 <br><br>A.64/125<br><br>B.4/125<br><br>C.64/5<br><br>D.12/5
Amiraneli [1.4K]
The answer is d. 12/5
4 0
2 years ago
Which type of display would be the most appropriate to compare the sales of 2 different stores for a ten year period?
satela [25.4K]
A line graph? I don't understand the question as much but a line graph would do if thats what ur looking for
Hope this is somehow helpful!
8 0
3 years ago
Identify the quadratic function(s). (Select all that apply.)
Katen [24]

General Idea:

The quadratic function of the form ax^2+bx+c=0.

Applying the concept:

Simplifying the equation in option A, we get...

A) \; 8 - 5x = 4(3x - 1) \\Distributing \; 4 \; in \; right \; side \; of \; the \; equation. \\ \\ 8 - 5x = 12x - 4\\ The \; equation \; is \; a \; linear \; equation \; with \; variable \; on \; both \; sides.

Simplifying the equation in option B, we get...

B) \; \; (4a + 2)(2a - 1) + 1 = 0\\ Multiplying \; First \; \; Outer \; \;  Inner \; \;  Last \;  terms\; in\;  the \; left \; side.\\ \\ 4a \cdot 2a + 4a \cdot -1 + 2 \cdot 2a + 2 \cdot -1 + 1 = 0\\ \\ 8a^2-4a+4a-2+1=0\\ Combining \; like \; terms \; \\ \\ 8a^2 - 1 = 0\\ Above \; is \; a \;  Quadratic \; Equation!

Simplifying the equation in Option C, we get...

C)\; \; 2y + 2(3y - 5) = 0\\ Distributing \; 2 \; in \; left \; side\\ \\ 2y+6y-10=0\\ Combining \; like \; terms\\ \\ 8y - 10 = 0\\ Above \; Equation \; is \; linear \; equation

Simplifying the equation in Option D, we get

D) \;2b(b - 7) + b = 0\\ Distributing \; 2b\; in \;the \;left\; side \;of \;the\;equation\\ \\ 2b \cdot b - 2b \cdot 7+b=0\\ Simplify \; in \; the \; left \; side \; of \; the \; equation\\ \\ 2b^2-14b+b=0\\ Combine \; like \; terms\\ \\ 2b^2-13b=0\\ Above \; equation \;is \;a \; Quadratic\;Equation!

<u>Conclusion:</u>

Option B) & Option D) are quadratic equation!

7 0
3 years ago
Read 2 more answers
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