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kifflom [539]
3 years ago
9

Use transformation to solve this equation. -3 2/3x = 22

Mathematics
1 answer:
diamong [38]3 years ago
5 0

answer to the problem is x=-33\16

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Determine the number of real solutions for each of the given equations. Equation Number of Solutions y = -3x2 + x + 12 y = 2x2 -
rosijanka [135]

Answer:

Step-by-step explanation:

Our equations are

y = -3x^2 + x + 12\\y = 2x^2 - 6x + 5\\y = x^2 + 7x - 11\\y = -x^2 - 8x - 16\\

Let us understand the term Discriminant of a quadratic equation and its properties

Discriminant is denoted by  D and its formula is

D=b^2-4ac\\

Where

a= the coefficient of the x^{2}

b= the coefficient of x

c = constant term

Properties of D: If D

i) D=0 , One real root

ii) D>0 , Two real roots

iii) D<0 , no real root

Hence in the given quadratic equations , we will find the values of D Discriminant  and evaluate our answer accordingly .

Let us start with

y = -3x^2 + x + 12\\a=-3 , b =1 , c =12\\D=1^2-4*(-3)*(12)\\D=1+144\\D=145\\D>0 \\

Hence we have two real roots for this equation.

y = 2x^2 - 6x + 5\\

y = 2x^2 - 6x + 5\\a=2,b=-6,c=5\\D=(-6)^2-4*2*5\\D=36-40\\D=-4\\D

Hence we do not have any real root for this quadratic

y = x^2 + 7x - 11\\a=1,b=7,-11\\D=7^2-4*1*(-11)\\D=49+44\\D=93\\

Hence D>0 and thus we have two real roots for this equation.

y = -x^2 - 8x - 16\\a=-1,b=-8,c=-16\\D=(-8)^2-4*(-1)*(-16)\\D=64-64\\D=0\\

Hence we have one real root to this quadratic equation.

7 0
3 years ago
What’s the answer ?
Misha Larkins [42]

Answer:

3 one ofx+2 And 4th one x4

6 0
3 years ago
What is 28.5 rounded to the nearest one
kumpel [21]

Answer:

29

Step-by-step explanation:

anythin0.5 or higher you round up so for 28.5 you round up to 29.

hope this helps. :)

8 0
3 years ago
Read 2 more answers
An experiment is carried out 400 times.
MissTica

Answer:

You would expect the outcome to be void 240 times

Step-by-step explanation:

1000 x 0.24

6 0
3 years ago
May I please get help with other this problem for I am confused as I have tried multiple times to get the right answer
Aleks [24]

Using pythagoras

\begin{gathered} x^2=16^2+12^2 \\ x^2=256+144 \\ x^2=400 \\ \text{Take the square root} \\ x=20 \end{gathered}

The final answer

20

5 0
1 year ago
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