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maks197457 [2]
3 years ago
12

Solve the inequality.           3m ≤ –9 A.m ≥ –3 B.m ≤ –3  C.m ≥ 6   D.m ≤ –6

Mathematics
1 answer:
marin [14]3 years ago
6 0
3m \leq -9\ /:3 \ \ \ \Rightarrow\ \ \ m \leq -3\ \ \ \Rightarrow\ \ \ Ans.\ B
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Please give the measure of NPQ and explain how you got it
anygoal [31]

Answer:

C

Step-by-step explanation:

NQP is a triangle. It has 3 angles given.

We know

<em>sum of 3 angles in a triangle is 180 degrees</em>

<em />

We are Given:

∠N = 2x

∠Q = 2x + 2

∠P = 134

THus, we can write and solve for x first:

∠N + ∠Q + ∠P = 180

2x + 2x + 2 + 134 = 180

4x + 136 = 180

4x = 180 - 136

4x = 44

x = 44/4

x = 11

Now, measure of ∠NQP is 2x + 2, so substituting the value of "x", we have:

2x + 2 = 2(11) + 2 = 22 + 2 = 24 degrees

So,

∠NQP = 24°

Correct answer is C

4 0
3 years ago
What comes next in this pattern? 7/2, 6/3, 5/4, ... 4/9 4/7 4/5
VARVARA [1.3K]

Answer:4/3

4/3

Step-by-step explanation:

3 0
2 years ago
A rectangle has a length of 3x+5 units and a width of x+5 units. A second rectangle has an area of 4x^2-5x+6 square units. What
natima [27]

Answer:

7x^2+15x+31

Step-by-step explanation:

(3x+5)(x+5)

FOIL

3x^2+15x+5x+25

(3x^2+20x+25)+(4x^2-5x+6) = 7x^2+15x+31

7 0
3 years ago
Read 2 more answers
3. Find the value of p in each of the following when f(x) is divided by d(x), with the help of remainder theorem:
ipn [44]

The remainder theorem says that dividing a polynomial <em>f(x)</em> by a 1st-degree polynomial <em>g(x)</em> = <em>x</em> - <em>c</em> leaves a remainder of exactly <em>f(c)</em>.

(a) With <em>f(x)</em> = <em>px</em> ³ + 4<em>x</em> - 10 and <em>d(x)</em> = <em>x</em> + 3, we have a remainder of 5, so

<em>f</em> (-3) = <em>p</em> (-3)³ + 4(-3) - 10 = 5

Solve for <em>p</em> :

-27<em>p</em> - 12 - 10 = 5

-27<em>p</em> = 27

<em>p</em> = -1

(b) With <em>f(x)</em> = <em>x</em> + 3<em>x</em> ² - <em>px</em> + 4 and <em>d(x)</em> = <em>x</em> - 2, we have remainder 8, so

<em>f</em> (2) = 2 + 3(2)² - 2<em>p</em> + 4 = 8

-2<em>p</em> = -10

<em>p</em> = 5

(you should make sure that <em>f(x)</em> was written correctly, it's a bit odd that there are two <em>x</em> terms)

(c) <em>f(x)</em> = 2<em>x</em> ³ - 4<em>x</em> ² + 6<em>x</em> - <em>p</em>, <em>d(x)</em> = <em>x</em> - 2, <em>R</em> = <em>f</em> (2) = 18

<em>f</em> (2) = 2(2)³ - 4(2)² + 6(2) - <em>p</em> = 18

12 - <em>p</em> = 18

<em>p</em> = -6

The others are done in the same fashion. You would find

(d) <em>p</em> = 14

(e) <em>p</em> = -4359

(f) <em>p</em> = 10

(g) <em>p</em> = -13/2 … … assuming you meant <em>f(x)</em> = <em>x</em> ⁴ + <em>x</em> ³ + <em>px</em> ² + <em>x</em> + 20

8 0
3 years ago
okay so I know this has nothing to do with school but this creepy guy is staring at me!! he is way older than me and I am scared
RoseWind [281]
Oh dear, this is so troll but acting oblivious is probably what I would do, and if action is taken, well...run xD
8 0
3 years ago
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