6k+10.5=3k+12
-10.5 -10.5
6k=3k+1.5
-3k -3k
3k=1.5
Answer:
19 seconds.
Step-by-step explanation:
Given that the clock was exactly on time at 7am, and at 1pm the clock was 228 seconds late, to determine, at that rate, how slow was the clock half an hour, the following calculation must be performed:
1 PM = 13:00
13 - 7 = 6
228/6 = 38
38/2 = 19
Thus, every half hour the clock is delayed 19 seconds.
F(x) = 1/(x+2) & g(x) = x/(x-3)
(f(x) + g(x) = 1/(x+2) + x/(x-3). Reduce to same denominator:
1/(x+2) + x/(x-3) =(x-3) + x(x-3)/(x+2).(x-3) ==> (x²+3x-3)/(x+2).(x-3)
Answer:I think a is:78.3 since it would be the same and since 0 doesn't have a value.
I think b is: 139.5 because all you are doing is subtracting 287.1-147.6