Hyp^2 = leg1^2 + leg2^2
hyp^2 -leg1^2 = leg2^2
17^2 - 8^2 = leg2^2
leg2^2 = 289 -64
leg2^2 = 225
leg2 = 15
The approximate age of a woman whose normal systolic pressure measures 125 mm Hg is 31
The function is given as:

When the normal systolic pressure is 125, it means that:

So, we have:

Subtract 125 from both sides of the equation


Rewrite the equation as:

Using a graphing calculator, we have:

But age cannot be negative.
So, we have:

Approximate

Hence, the age of the woman is 31
Read more about quadratic functions at:
brainly.com/question/11441586
Does 2 is included in the square root?
sq.rt (44/2) ? or (sq.rt 44)/2
Answer:Yes, I checked.. it is option 2
Step-by-step explanation:
Answer:
30-2x
Step-by-step explanation:
yuson has to finish am total of 30 hours in community service
she does 2 hours each day
in x days, hour of service done=2x
after x days hours of service left=30-2x
therefore the linear equation representing the hours yuson has left after x days is:
30-2x