Answer:
≈ 0.52
Step-by-step explanation:
P( head ) = 2/3 , P( tail ) = 1/3
when a head is tossed ; Gambler A wins $1
when a tail is tossed : Gambler B wins $1
<u>Determine the P( Gambler A wins the game ) if he starts with I dollars</u>
Assuming I = $1
n = 5
p ( head ) = P( winning ) = 0.66
p( losing ) = 0.33
applying the conditional probability in Markov which is ;
Pₓ = pPₓ₊₁ + (1 - p) Pₓ₋₁
P( 1) = 0.66P₂ + 0.33P₀
resolving the above using with Markov probability
P( 1 ) = 0.51613
hence the probability of Gambler A winning the game if he starts with $1
≈ 0.52
Answer:(-1,2)
Step-by-step explanation:
The standard for of this equation is x – y = 0
Firstly, options A and D are not in standard form, so they are not options.
To decided between B and C, we choose a point on the line and see if it works. For example, we'll use (2, 2).
x – y = 0
2 - 2 = 0
0 = 0
This is true for option C. Therefore, it is correct.
True.
The square root of 12: √12 = 3.464101......
This continues indefinitely and can not be represented as a ratio of two integers.
So it is not rational, that is irrational.
