You will take 140 times 5 since that is the amount she made so you times it buy the price she earns then after you do that subtract it buy 650 since that is what you have to pay
140 x 5 = 700
700 - 650 = 50
so she made a profit of 50
Answer:
6
Step-by-step explanation:
2x-m
When you substitue in the values for x and m:
2(4)-2
Now you can solve the equation:
2(4)-2
8-2
6
So this leads to the answer
2x-m=6 or 2(4)-2=6
First, we are going to find the radius of the yaw mark. To do that we are going to use the formula:
![r= \frac{c^2}{8m} + \frac{m}{2}](https://tex.z-dn.net/?f=r%3D%20%5Cfrac%7Bc%5E2%7D%7B8m%7D%20%2B%20%5Cfrac%7Bm%7D%7B2%7D%20)
where
![c](https://tex.z-dn.net/?f=c)
is the length of the chord
![m](https://tex.z-dn.net/?f=m)
is the middle ordinate
We know from our problem that the tires leave a yaw mark with a 52 foot chord and a middle ornate of 6 feet, so
![c=52](https://tex.z-dn.net/?f=c%3D52)
and
![m=6](https://tex.z-dn.net/?f=m%3D6)
. Lets replace those values in our formula:
![r= \frac{52^2}{8(6)} + \frac{6}{2}](https://tex.z-dn.net/?f=r%3D%20%5Cfrac%7B52%5E2%7D%7B8%286%29%7D%20%2B%20%5Cfrac%7B6%7D%7B2%7D%20)
![r= \frac{2704}{48} +3](https://tex.z-dn.net/?f=r%3D%20%5Cfrac%7B2704%7D%7B48%7D%20%2B3)
![r= \frac{169}{3} +3](https://tex.z-dn.net/?f=r%3D%20%5Cfrac%7B169%7D%7B3%7D%20%2B3)
![r= \frac{178}{3}](https://tex.z-dn.net/?f=r%3D%20%5Cfrac%7B178%7D%7B3%7D%20)
Next, to find the minimum speed, we are going to use the formula:
![s= \sqrt{15fr}](https://tex.z-dn.net/?f=s%3D%20%5Csqrt%7B15fr%7D%20)
where
![f](https://tex.z-dn.net/?f=f)
is <span>drag factor
</span>
![r](https://tex.z-dn.net/?f=r)
is the radius
We know form our problem that the drag factor is 0.2, so
![f=0.2](https://tex.z-dn.net/?f=f%3D0.2)
. We also know from our previous calculation that the radius is
![\frac{178}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B178%7D%7B3%7D%20)
, so
![r= \frac{178}{3}](https://tex.z-dn.net/?f=r%3D%20%5Cfrac%7B178%7D%7B3%7D)
. Lets replace those values in our formula:
![s= \sqrt{(15)(0.2)( \frac{178}{3}) }](https://tex.z-dn.net/?f=s%3D%20%5Csqrt%7B%2815%29%280.2%29%28%20%5Cfrac%7B178%7D%7B3%7D%29%20%7D%20)
![s= \sqrt{178}](https://tex.z-dn.net/?f=s%3D%20%5Csqrt%7B178%7D%20)
![s=13.34](https://tex.z-dn.net/?f=s%3D13.34)
mph
We can conclude that Mrs. Beluga's minimum speed before she applied the brakes was
13.34 miles per hour.
286. you just subtract the two numbers