If we know the measure of two of the three angles of a triangle, since the sum of the angles in a triangle aways is 180º, we can write the equation for angles a, b and c:
Let's suppose we know x and y, then z is:
Find a vector~a=~ABwhereA= (2,3) andB= (5,7) then draw its equivalentrepresentations starting at pointC= (0,2) and a unit vector
1 answer:
Answer:
Step-by-step explanation:
Given that vector a has starting point (2,3) and end point (5,7)
Direction ratios of AB = (5-2, 7-3) = (3,4)
Magnitude =
a) Starting point (0,2)
Distance= 5 units from (0,2) and direction ratios (3,4)
So the point will be of them (0+3t, 2+4t)
Distance = 5t units. So t =1
So point is (3,6)
b) When starting point =(0,5)
End point with same direction would be
(0+3, 5+4) = (3,9)
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<h2>Part 1)</h2>
Let's analyze each part of the function:
FROM x = 0 TO x = 5:
We can find the equation of this line by using The Slope-Intercept Form of the Equation of a Line, that states:
So the y-intercept here is and
, therefore:
FROM x = 0 TO x = 5:
From the previous line, we know that at the output is:
So the point lies on both lines.
For this new line, the slope is
So, with the Point-Slope Form of the Equation of a Line we can find the equation of this other line:
So:
The graph is shown below.
<h2>Part 2)</h2>The graph of the linear function is a line with slope
and
at
. From the items, we can assure that the following equations are linear functions:
In conclusion, the other functions are nonlinear and they are: