The equation is already in Standard Form.
Your answer would be X=8 and Y=11.
When we add rational numbers we simply add or subtract the fraction or part of a whole so in this particular equation we would subtract 1 from 4 because adding a negative means the same thing. We then subtract 2/3 from 3 and get 2 1/3 Comment below if more details are required

$=\sqrt{4^2}\times\sqrt{2^2\cdot3}$
$=4\times2\sqrt3=8\sqrt3$
Can you show the choices you have