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mylen [45]
3 years ago
9

Round 7.4521 to 2 significant figures

Mathematics
2 answers:
Troyanec [42]3 years ago
5 0
7.5 would be my best guess
Karo-lina-s [1.5K]3 years ago
3 0
Round 7.4521 to 2 significant figures ....
the answer would be 7.4521

7.4521=7.45
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Write the algebraic expression for the phrase <br> 10 more than t
Scilla [17]

 

The algebraic expression is:

E = t + 10

                                                       

 

4 0
3 years ago
Read 2 more answers
Help me please thanks.
kap26 [50]

Answer:

Step-by-step explanation:

4 0
3 years ago
I need help on this math problem.
OLEGan [10]

B: (0, a)

C should have the same y value as B

D: (a,0)

C should have the same x value as D


So point C is (a,a)

Since point A is on the origin, its point is (0,0)


You use the slope formula and plug in point A and C:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m=\frac{a-0}{a-0}

m=\frac{a}{a}

m = 1


So the value that belongs in the green box is 1


6 0
3 years ago
Jon ate too many holiday cookies and gained 2.2 kilograms in December. Then he went on a diet and lost 1.5 kilograms in January.
gogolik [260]

Answer:

Jon lost a total of 3 kilograms in these 3 months.

Step-by-step explanation:

Weight that Jon gained in December = 2.2 kilograms

Weight that Jon lost in January = 1.5 kilograms

Weight that Jon lost in February = 3.7 kilograms

Overall Change in his weight = Total Weight he gained - Total weight he Lost

Total weight he gained is 2.2 kilograms as he only gained weight in December. Total weight he lost will be sum of weights he lost in January and February.

So, total weight Jon lost = 1.5 + 3.7 = 5.2 kilograms

Thus,

Total change in Jon's Weight = 2.2 - 5.2 = -3.0 kilograms

This shows that Jon lost a total of 3 kilograms in these 3 months.

Conclusion:

The statement that best describe the total change in his weight is: Jon lost a total of 3 kilograms in these 3 months

5 0
2 years ago
Read 2 more answers
3=c/5+2... how do I solve for c??
expeople1 [14]
Primeiro Você IRA Dividir o c (APENAS Colocar 5 + 2 embaixo do c). Depois faça a soma 5 + 2 = 7. Então faça o mmc (mínimo múltiplo comum) entre 7 e 1(o 1 é invisível, mas continua estando embaixo do 3). Deu 7 o mmc. Transforme seus números em frações, com o denominador 7. Transforme os números em frações o 3 virá 21, pois você divide em baixo e multiplica em baixo, e o c continua normal, pois já estava em baixo de 7. Como é para descobrir uma incógnita você tira os denominadores e ficará 21 = c.

3 = c/5 + 2
3 = c/7
21/7 = c/7
21 = c
4 0
3 years ago
Read 2 more answers
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