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vitfil [10]
3 years ago
5

The yield in bushels from a grove of orange trees is given by Y = x(600 − x), where x is the number of orange trees per acre. Ho

w many trees will maximize the yield?
Mathematics
1 answer:
kotykmax [81]3 years ago
8 0

Answer:

90000

Step-by-step explanation:

Y = x(600 - x)

Let's rearrange the equation so that we have

Y = x(-x + 600)

Y = -x² + 600

When you take a look at parabolas, we know that their maximum or minimum values are usually on the axis of symmetry. This axis of symmetry has an equation of

x = -b/2a,

In this question, the axis of symmetry is

x = -600 / -2

x = 300

This means that planting 300 trees will maximize your yield. If you substitute for x = 300 into the equation, the maximum yield will be

y = 300 (600 - 300)

y = 90000.

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A water sprinkler covers a circular area with a diameter of 20 feet. If it is set to cover only an arc measuring 120 degrees, wh
Wewaii [24]

<u>Answer:</u>

The sprinkler will cover 104.66 square feet

<u>Explanation:</u>

A water sprinkler covers a circular area with a diameter D=  20 feet

and radius r = 10 feet

Arc measuring degrees = 120 degree

Area of the Arc = \frac{120}{360} \times \pi \times r^2

                         = \frac{1}{3} \times \pi \times 10^2

                         = \frac{1}{3} \times 3.14 \times 10 \times 10

                         = 104.66

The sprinkler will cover an arc area covering 104.66 square feet

4 0
3 years ago
Find the Expression OF this equation.<br>c/3 / ac/4<br><br>QUESTION C
Fiesta28 [93]

Answer:

See below

Step-by-step explanation:

(a) \:  \: x =  \frac{c}{3}  \\  \\  \implies \:  {x}^{2}  =   { \bigg( \frac{c}{3} \bigg) }^{2}   \\  \\ \bold{\implies \:  {x}^{2}  =     \frac{ {c}^{2} }{9} } \\  \\ (b) \:  \: x + y =  \frac{c}{3}  +  \frac{ac}{4}  \\  \\\implies \:  \bold{x + y  =  \frac{4c + 3ac}{12} } \\  \\  \frac{xy}{z}  =  \frac{ \frac{c}{3}  \times  \frac{ac}{4} }{ \frac{ {a}^{2} }{2c + 1} }  \\  \\ =  \frac{ \frac{ac ^{2} }{12} }{ \frac{ {a}^{2} }{2c + 1} }  \\  \\  =  \frac{a {c}^{2} }{12}  \times  \frac{2c + 1}{ {a}^{2} }  \\  \\  \implies\bold{\frac{xy}{z}  =  \frac{ {c}^{2}(2c + 1) }{12a} }

8 0
2 years ago
Triangle MNP is transformed according to the rule T(4,–1). What is the y-coordinate of M”?
koban [17]
T(4,-1) means move 4 units to the right and 1 unit down.

Based on the image, M(-3,4) ; N(-2,1) ; P(-4,2)

So,
M:
-3 move 4 units to the right becomes 1 
4 move 1 unit down becomes 3
M'(1,3)

N
-2 move 4 units to the right becomes 2
1 move 1 unit down becomes 0
N"(2,0)

P
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7 0
3 years ago
Read 2 more answers
2sec^2x - secx - 1 = 0
Ivenika [448]
What are you trying to do here?
Solve the graph, or make it appear as something else?

First, we're going to take one sec (x) out so that we get:
sec (x) (2sec (x) -1 -1) = 0

sec (x) (2sec (x) -2) = 0


Then we're going to separate the two to find the zeros of each because anything time 0 is zero.

sec(x) = 0

2sec (x) - 2 = 0

Now, let's simplify the second one as the first one is already.

Add 2 to both sides:

2sec (x) = 2

Divide by 3 on both sides:

sec (x) = 1


I forgot my unit circle, so you'd have to do that by yourself. Hopefully, I helped a bit though!
8 0
3 years ago
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Firdavs [7]
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7 0
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