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vitfil [10]
3 years ago
5

The yield in bushels from a grove of orange trees is given by Y = x(600 − x), where x is the number of orange trees per acre. Ho

w many trees will maximize the yield?
Mathematics
1 answer:
kotykmax [81]3 years ago
8 0

Answer:

90000

Step-by-step explanation:

Y = x(600 - x)

Let's rearrange the equation so that we have

Y = x(-x + 600)

Y = -x² + 600

When you take a look at parabolas, we know that their maximum or minimum values are usually on the axis of symmetry. This axis of symmetry has an equation of

x = -b/2a,

In this question, the axis of symmetry is

x = -600 / -2

x = 300

This means that planting 300 trees will maximize your yield. If you substitute for x = 300 into the equation, the maximum yield will be

y = 300 (600 - 300)

y = 90000.

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a birthday cake at the bakery was $30 originally. During a sale, a discount of 28% was given. A further 15% discount was given t
V125BC [204]

Answer:

$18.36

Step-by-step explanation:

In this question, we have to find the cost of the cake for the customer who orders a month early.

We know that the original price of the cake is $30.

We also know that there was a 28% discount and a 15% discount added to the purchase.

Remember, You don't add discount percentages together, you discount the prices separately.

Solve:

First, apply the 28% discount.

30 · 0.28 = 8.40

30 - 8.40 = 21.60

Now apply the 15% discount to the new price.

21.60 · 0.15 = 3.24

21.60 - 3.24 = $18.36

They needed to pay $18.36 for the cake.

6 0
3 years ago
How can you write the expression with rationalized denominator? 2+sqrt3(3)/sqrt3(6)
joja [24]
So we have a 6 at the bottom, and the root is 3, so hmm how to take it out, simple enough, just let's get something to make the 6 a 6³, so it comes out of the root

so 

\bf \cfrac{2+\sqrt[3]{3}}{\sqrt[3]{6}}\cdot \cfrac{\sqrt[3]{6^2}}{\sqrt[3]{6^2}}\implies \cfrac{(2+\sqrt[3]{3})(\sqrt[3]{6^2})}{(\sqrt[3]{6})(\sqrt[3]{6^2})}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{3}\cdot \sqrt[3]{36}}{\sqrt[3]{6^3}}
\\\\\\
\cfrac{2\sqrt[3]{36}+\sqrt[3]{3\cdot 36}}{6}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{108}}{6}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{3^3\cdot 4}}{6}
\\\\\\
\cfrac{2\sqrt[3]{36}+3\sqrt[3]{ 4}}{6}
8 0
3 years ago
Complete the equations bellow.
Step2247 [10]
What equations? Explanation:
7 0
2 years ago
Please help with this
omeli [17]

Answer:

y =  \frac{1}{8} x - 3

Step-by-step explanation:

Formula for straight lines:

y = mx + b

where m = slope, b = constant

Given:

y-intercept = -3 (0, -3)

m = ⅛

Substitute into formula to find b.

- 3 =  \frac{1}{8} (0) + b \\  - 3 = 0 + b \\ b =  - 3

Substitute b into original formula

y = mx + b \\ y =  \frac{1}{8} x + ( - 3) \\ y =  \frac{1}{8} x - 3

4 0
2 years ago
Evaluate 3x+6y when x= -3, y=6
sesenic [268]

Hey there!!!

Given equation - 3x+6y

x is given as -3

y is given as 6

Plugin these values to get the final answer

3 ( -3 ) + 6 ( 6 )

-9 + 36

= 27

27 is the final and the required answer

Hope my answer helps!

3 0
2 years ago
Read 2 more answers
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