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Leni [432]
3 years ago
8

Write an expression equal to 7(3x +4)

Mathematics
2 answers:
Fantom [35]3 years ago
7 0
I'm pretty sure this will work 7 *3x + 7*4
kati45 [8]3 years ago
5 0
21x + 28. just distribute the 7.
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Please help and thank you
djyliett [7]

The answer would be D

G(x) = (X-4)^2

8 0
3 years ago
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Help me please? :( (;´༎ຶД༎ຶ`)(;´༎ຶД༎ຶ`)(;´༎ຶД༎ຶ`)
Gnesinka [82]

Answer:

a) 22:53

b)213 min

Step-by-step explanation:

c) 10 17 + 4 = 14 17

she has 2 minutes to spare

5 0
3 years ago
Help last 3 questions thanks so much!
deff fn [24]

Answer:

did that first one its false

A= 53, B= 100, C= 27 (the last option)

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8 0
3 years ago
Convert 0.0000001 to a power of 10.<br><br> 107<br> 10−7<br> 106<br> 10−6
valina [46]
Since you have to move the decimal point the the right by 7 places to get the decimal point after the one.  You must multiply by 1/10 seven times, which is the same as:

10^-7
4 0
3 years ago
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Total world consumption of iron was approximately 900 million tons in 1993. If consumption had increased by 2.5% each year and t
Lilit [14]

Step-by-step explanation:

We can model the annual consumption of iron by the equation

c = 900 million tons x 1.025^n, where

n is the number of years after 1993 and

c is the consumption for that year.

An estimate for the total consumption of iron can now be obtained by integrating this equation with respect to a dummy variable, x from 0 to n.

C = 900*10^6* \int\limits^n_0 {1.025^x} \, dx

This equation simplifies to

C = 900 million tons x (1.025^n - 1) / ln(1.025), where

x is a dummy variable and

C is the total consumption of iron n years after 1993.

Let R be the amount of iron remaining at n years after 1993, so

R = 480 billion tons - C

R = 480 billion tons - 900 million tons x (1.025^n - 1) / ln(1.025)

We need to find the value of n when R is 0, so

0 = 480 billion tons - 900 million tons x (1.025^n - 1) / ln(1.025)

Simplify this equation to obtain

n = 107.4

So the iron will run out in the year 1993 + 107 = 2100

6 0
2 years ago
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