Answer:
6 tanks would required to fill in equal number of fishes in each tank.
Step-by-step explanation:
Given:
Number of Angel Fish = 12
Number of Sword tail fish =24
Number of guppies =30
We need to find the greatest number of tanks containing equal number of fishes.
Solution:
to find the greatest number of tanks containing equal number of fishes we will find the greatest prime factors of the number.
Multiples of 12 = ![2\times 2\times 3](https://tex.z-dn.net/?f=2%5Ctimes%202%5Ctimes%203)
Multiples of 24 = ![2\times 2\times 2\times 3](https://tex.z-dn.net/?f=2%5Ctimes%202%5Ctimes%202%5Ctimes%203)
Multiples of 30 = ![2\times3\times 5](https://tex.z-dn.net/?f=2%5Ctimes3%5Ctimes%205)
From above we get the the Greatest common prime factor = ![3\times 2 =6](https://tex.z-dn.net/?f=3%5Ctimes%202%20%3D6)
Hence 6 tanks would required to fill in equal number of fishes in each tank.
9.) <span>1/2(4x-6)=11
</span>Multiply 4 and -6 by 1/2
2x-3=11
Add 3 to both sides
2x=14
Divide 14 by 2
Final Answer: x=7
10.) 2/3(6x-9)=-34
Multiply 6 and -9 by 2/3
4x-6=-34
Add 6 to both sides
4x=-34
Divide -34 by 4
Final Answer: x=-8.5
Ok let’s solve it
5(x-2)^2-20=0
first let’s foil (x-2)
5(x^2-4x+4) -20=0
now distribute the 5
5x^2 -20x +20 -20 = 0
combine like terms
5x^2-20x=0
take the gcf
5x(x-4)=0
x=0, 4
solutions are (4,0) and (2, -20) because the original vertex form a(x-h)^2+k
30x 10= 300x 10= 3000. Times by ten