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Nat2105 [25]
3 years ago
6

The length of one leg of a right triangle is 48 ft, and the length of the hypotenuse is 50 ft. What is the length of the other l

eg?
14.0 feet

12.0 feet

3.5 feet

9.9 feet
Mathematics
2 answers:
Brums [2.3K]3 years ago
6 0
Other leg = √50² - 48² = √2500 - 2304 = √196 = 14 feet

Answer is A

Hope it helps!
erica [24]3 years ago
3 0
Use the Pythagorean theorem. The answer is 14 feet.
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Function F(x)=x+1 and g(x)=5x+1 find the f(4)=g(x+1)
Lapatulllka [165]

The function of f(4) = g(x+1) gives the value of x that is -1/5.

<h3>What is the function addition?</h3>

It is the addition of two functions similar to the addition of any two polynomial functions.

Given;

F(x)=x+1

g(x)=5x+1

We need to find f(4)=g(x+1)

First substitute x = 4 in f(x)

F(x)=x+1

F(4) = 4 + 1

F(4) =  5

Now substitute x = x + 1 in g(x)

g(x)=5x+1

g(x + 1) = 5(x + 1) + 1

g(x + 1) = 5(x + 1) + 1

g(x + 1) = 5x + 5 + 1

g(x + 1) = 5x + 6

Then ,

F(4) = g(x + 1)

5 = 5x + 6

5x = 5 - 6

5x = -1

x = -1/5.

The function of f(4) = g(x+1) gives the value of x that is -1/5.

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7 0
2 years ago
I need help on this question
Vadim26 [7]

Answer:

4.8ft

Step-by-step explanation:

3 0
3 years ago
1,49,1625,3649,..... what is the next term in this series?
gayaneshka [121]
The series would be look like this with adding the next number
<span>1,49,1625,3649,6481

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What is the value of the expression 3y-4xy^2 when x=3 and y=-6
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3 years ago
Complete the square on the following quadratic x2+10x+9=0
kakasveta [241]
Given a quadratic equation x^{2} +ax+c=0

1. the first thing we do when we want to compete the square, is write the coefficient of x as 2 times a number.

In our case the coefficient of x is 10, so we write 10 as 2*5

2. then we write + 5^{2} and - 5^{2} to the expression:

x^{2} +2*5*x+ 5^{2} -5^{2}+9=0

(x^{2} +2*5*x+ 5^{2}) -25+9=0

(x+5)^{2}-16=0



Answer: (x+5)^{2}-16=0
8 0
3 years ago
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