Well, you need to partition your hard drive. Partitioning your hard drive designates usable space on your hdd.
And you need to format your hard drive. Formatting installs a file system on to your hard drive, it allows the operating system to read, write and overall understand the data stored on the disk. Without it, an OS cannot keep track of file locations, nor can it typically identify already used sectors (space) on a hdd.
However, neither of these two concepts are tests.
1. ughhhh not entirely sure but B, 2. again not entirely sure should be B as well and finally 3.is D remember these are not always the answer just most likely what one person thinks
Connection to the gigabit ethernet network must be done with Cat6 Cable. Using the wireless ethernet router as the network device and connecting the cable to the printer must be done with Cat5e Cable.
We can arrive at this answer because:
- The Cat6 Cable will be responsible for establishing a bridge between the gigabyte Ethernet and the network device, allowing data delivery to be made between the two systems.
- This connection must be made with a wireless device, to keep it more stabilized and it needs, mainly, for the notebook to receive the internet signal. This will be done using the wireless ethernet router.
- The printer needs a softer, less rigid connection, so a Cat5e cable will be a convenient option.
In this case, we can see that using these devices will allow Lori to have a more stable and efficient connection to meet her needs.
More information on network connection at the link:
brainly.com/question/8118353
Answer:
a. 118.20.210.254
Explanation:
Here are the few characteristics of Class A:
First bit of the first octet of class A is 0.
This class has 8 bits for network and 24 bits for hosts.
The default sub-net mask for class A IP address is 255.0.0.0
Lets see if the first bit of first octet of 118.20.210.254 address is 0.
118 in binary (8 bits) can be represented as : 1110110
To complete 8 bits add a 0 to the left.
01110110
First bit of the first octet of class A is 0 So this is class A address.
For option b the first octet is : 183 in the form of bits = 10110111 So it is not class A address
For option c the first octet is 215 in the form of bits = 11010111 So it is not class A address
For option d the first octet is 255 in the form of bits = 11111111. The first bit of first octet is not 0 so it is also not class A address.
