Answer:
Demonstrate the register addressing mode for the following instructions. Also what addressing mode belongs to these instructions?
1. MOV CX, [BX+DI]
2. MOV AX, ARRAY[CX]
3. MOV BX, [CX+DI+6]
Answer:
115200000 bits
Explanation:
Given Data:
Total Time = 3 minute = 3 x 60 sec = 180 sec
Sampling rate = 40,000 bits / sample
Each sample contain bits = 16 bits /sample
Total bits of song = ?
Solution
Total bits of song = Total Time x Sampling rate x Each sample contain bits
= 180 sec x 40,000 bits / sec x 16 bits /sample
= 115200000 bits
= 115200000/8 bits
= 14400000 bytes
= 144 MB
There are total samples in one second are 40000. Total time of the song is 180 seconds and one sample contains 16 bits. so the total bits in the song are 144 MB.
Answer:
Computer is called versatile and diligent device because it is used in almost all the fields for various purposes and it can perform the task repeatedly without loosing its speed and accuracy for long time.
Answer:
The answer to this question is given below in the explanation section.
Explanation:
The selection sort algorithm step started from 0, and continue till the sorting is done.
The correct answer after selection sort algorithm at the 4th step is:D
[0,1,2,4,8,10].
The complete detail of step by step execution is shown in the attached document file.
