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nignag [31]
3 years ago
6

Explain the tangent line problem

Mathematics
1 answer:
ale4655 [162]3 years ago
8 0

The Tangent Line Problem  1/3How do you find the slope of the tangent line to a function at a point Q when you only have that one point? This Demonstration shows that a secant line can be used to approximate the tangent line. The secant line PQ connects the point of tangency to another point P on the graph of the function. As the distance between the two points decreases, the secant line becomes closer to the tangent line.
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-5(-6k + 10) =<br> Help ASAP
Fudgin [204]

Answer:

<h2>30k - 50</h2><h2 />

Step-by-step explanation:

-5 (-6k + 10)

= 30k - 50

8 0
3 years ago
What is the quotient StartFraction 15 p Superscript negative 4 Baseline q Superscript negative 6 Baseline Over negative 20 p Sup
Kitty [74]

Answer:

-\frac{3p^8}{4q^3}

Step-by-step explanation:

\frac{15p^{-4}q^{-6}}{-20p^{-12}q^{-3}}  can be broken down into three fractions, coefficients, powers of p, powers of q.

-\frac{15}{20}\cdot\frac{p^{-4}}{p^{-12}}\cdot\frac{q^{-6}}{q^{-3}}

Simplify the first fraction, then simplify the others by subtracting numerator exponents minus denominator exponents.

-\frac{3}{4} p^{-4-(-12)} q^{-6-(-3)} =-\frac{3}{4} p^8 q^{-3} = \alpha -\frac{3p^8}{4q^3}

8 0
3 years ago
Dose someone know hope to do this can someone help
Art [367]
The point where they intersect
5 0
3 years ago
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FREE BRAINLY PLZ HELP 50 PTS!!<br> Simplify -5(20 + 3)<br><br> -115<br> -103<br> 85<br> -97
ra1l [238]

Answer:

- 5(2 0 + 3) =  - 50 \times 20 +  - 5 \times 3 \\  =  - 100 - 15 \\  =  - 115 \\ thank \: you

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Find g: 3g + 15 − 12 + 3 − 2g + 4 = 1
lisov135 [29]

Answer:Group of answer choices

Step-by-step explanation:

What you first want to do is like and unlike terms so basically liketerms are terms withthe same sign and unlike terms are terms with diferent signs for instinse 3g and 2g are like terms so -33 and -9 and -9 and 9 are unlike terms so you just have to find the like and unlike terms to answer the question!

6 0
3 years ago
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