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nignag [31]
3 years ago
6

Explain the tangent line problem

Mathematics
1 answer:
ale4655 [162]3 years ago
8 0

The Tangent Line Problem  1/3How do you find the slope of the tangent line to a function at a point Q when you only have that one point? This Demonstration shows that a secant line can be used to approximate the tangent line. The secant line PQ connects the point of tangency to another point P on the graph of the function. As the distance between the two points decreases, the secant line becomes closer to the tangent line.
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Circle A is congruent to circle J. Chords BC, CF, EG, KL, LO, and MP are congruent.
coldgirl [10]

Answer:

its 1,4,5 i just did the test

Step-by-step explanation: //

6 0
3 years ago
Read 2 more answers
A triangle is placed in a semicircle with a radius of 5 yd, as shown below. Find the area of the shaded region.
Svetradugi [14.3K]

Answer:

  14.25 yd^2

Step-by-step explanation:

The triangle area is given by the formula ...

  A = 1/2bh

Here, the base is 10 yd, and the height is 5 yd, so ...

  triangle area = (1/2)(10 yd)(5 yd) = (5 yd)^2 = 25 yd^2

__

The semicircle is half the area of a circle with radius 5 yd, so its area is ...

  semicircle area = (1/2)π(5 yd)^2 = 12.5π yd^2 ≈ 39.25 yd^2

__

The shaded region is the difference between these areas:

  shaded area = 39.25 yd^2 -25 yd^2 = 14.25 yd^2

7 0
3 years ago
Please help me ?????!
lina2011 [118]
B and a. it goes down about two lines and then has a very more steep incline
5 0
3 years ago
Anybody bother to help???
Dovator [93]
Idk about number 4 but I think the other ones are correct

5 0
3 years ago
What is the answer to this question
Lesechka [4]

Remark

There's a lot you don't know here. Are DE and GF parallel? Is B a right angle? You can't assume that it is. The safest way to proceed is to give x in terms of 58 and B. You might get an answer that gives you something like 32 but I don't think you can say that unless you are told somewhere that ABC is a right angle triangle with the right angle at B.

So what to do.

<BAC = 58o                               That's because <BAC = <IAK They vertically opposite.

<ABC + <BAC + <ACB = 180o       All triangles have 180o

<ACB = 180 - 58 - <ABC                Solve for an unknown angle of a triangle.

<ACB = 122 - <ABC

x = <ACB                                       Vertically opposite angles.

x = 122 - <ABC                             Answer  It's 32 if ABC is a right angle.  

6 0
3 years ago
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