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2 years ago

Help. help. help.no link pls.

Mathematics

1 answer:

kondaur [170]2 years ago

8 0

Answer:

x + 2, x ≠ -2

Step-by-step explanation:

Note that F(x) = x^2 + 4x + 4 factors into (x + 2)^2, and that we are dividing this by g(x) = x + 2. The quotient is x + 2, which in this problem has been named h(x).

The quotient (f/g)(x) is therefore x + 2 EXCEPT that this is not defined at x = -2, because the denominator, x + 2, will be zero there, undefined.

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Helpp

Georgia [21]

Answer:

see explanation

Step-by-step explanation:

The average rate of change over the closed interval [ a, b ] is

$\frac{f(b)-f(a)}{b-a}$

here [ a, b ] = [ 0, 8 ]

f(b) = f(8) = $\frac{16-2}{40-6}$ = $\frac{14}{34}$ = $\frac{7}{17}$

f(a) = f(0) = $\frac{-2}{-6}$ = $\frac{1}{3}$

f(b) - f(a) = $\frac{7}{17}$ - $\frac{1}{3}$ = $\frac{4}{51}$

average rate of change = $\frac{\frac{4}{51} }{8}$ = $\frac{1}{102}$

7 0

2 years ago

Look at the PDF and look answer the question, pls do explain

gulaghasi [49]

Answer:

26 hamburgers.

Step-by-step explanation:

8 2/3=26/3 each hamburger takes 1/3 meat. So 26/3 ÷1/3=26

8 0

3 years ago

Read 2 more answers

Can somebody help me. Will Mark brainliest.

klasskru [66]

Answer:

choice 2

Step-by-step explanation:

8 0

2 years ago

Please find the answer and show your work so I can learn thanks!!

irga5000 [103]

Answer:

22.34 ${km}^{2}$

Step-by-step explanation:

The area of a circle:

A = π $r^{2}$

The problem gives the diameter of a circle, which is equal to 2*r.

If 5 1/3 = 2*r, then the radius is (16/3)/2 = 8/3.

Plugging this into the area equation,

A = π* ${{8/3}}^{2}$

A = $\frac{{64*π}}{9}$ or approximately 22.34 ${km}^{2}$

8 0

2 years ago

If each car has the same mass which car will require the longest time to come to a full stop

rosijanka [135]

Answer:

Car D

Step-by-step explanation:

Since the mass is the same, we need to depend on the speed. The lower the speed, the easier/faster to stop. The higher the speed, the longer it will take to come to a stop

5 0

3 years ago

Help. help. help.no link pls. ​

Help. help. help.no link pls.