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Kitty [74]
3 years ago
11

Simplify 7 • 8 – 9 + 36 ÷ 3 A) 45 B) 47 C) 57 D) 59

Mathematics
2 answers:
Gnoma [55]3 years ago
6 0
D 59. Simple use of order of operations were needed.
Dimas [21]3 years ago
5 0
   7 * 8 - 9 + 36 / 3
= 56 - 9 + 36 / 3
= 56 - 9 + 12
= 47 + 12
= 59..

Therefore the answer is 59
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A hat salesman earns a commission of 30% of all hat sales made. Yesterday he sold 3 hats for $90 each and 4 hats for $50 each. H
zalisa [80]
(30/100)(90*3+50*4)

(30/100)(270+200)

(30/100)(470)

$141.00


6 0
3 years ago
Read 2 more answers
-1/3x+2x=3 3/4 what does the variable represent?
svet-max [94.6K]
Start off by combining like terms on the LHS (the terms with x in them).

So we get \frac{-1}{3}x+2x= \frac{-1}{3}x+ \frac{6}{3}x= \frac{-5}{3}x

Replacing this result with what we had before on the LHS, we get \frac{-5}{3}x=3 \frac{3}{4}= \frac{9}{4}

⇒Solve for x (divide both sides \frac{-5}{3})
⇒Don't forget about reciprocity rules when dividing.  This is the same as multiplying both sides by \frac{3}{-5}

⇒x= \frac{9}{4}( \frac{3}{-5})

⇒x= -\frac{27}{20}=-1\frac{7}{20} ***This is a proper fraction
4 0
3 years ago
Read 2 more answers
What are the odds in favor of choosing a person at random who chose juice a?
stealth61 [152]

37:53

Step-by-step explanation:

Step 1 :

Given

Number of people choosing Juice A = 37

Number of people choosing Juice B = 32

Number of people choosing Juice C = 21

We need to find the odds in favor of choosing a person who chooses juice A

Step 2  :

Here the number of success is the number of people choosing juice A = 37

Number of failures is the number of the people not choosing juice A = Number of people choosing juice B + Number of people choosing juice C = 32+21 = 53

Hence the odds in favor of choosing a person who chooses juice A is 37:53

3 0
3 years ago
The speed at which cars travel on the highway has a normal distribution with a mean of 60 km/h and a standard deviation of 5 km/
oee [108]

The z-score of the speed value gives the measure of dispersion of the from

the mean observed speed.

The probability that the speed of a car is between 63 km/h and 75 km/h is

<u>0.273</u>.

The given parameters are;

The mean of the speed of cars on the highway, \overline x = 60 km/h

The standard deviation of the cars on the highway, σ = 5 km/h

Required:

The probability that the speed of a car is between 63 km/h and 75 km/h

Solution;

The z-score for a speed of 63 km/h is given as follows;

Z=\dfrac{x-\bar x }{\sigma }

Which gives;

Z=\dfrac{63-60 }{5 } = 0.6

From the z-score table, we have;

P(x < 63) = 0.7257

The z-score for a speed of 75 km/h is given as follows;

Z=\dfrac{75-60 }{5 } = 3

Which gives, P(x < 75) = 0.9987

The probability that the speed of a car is between 63 km/h and 75 km/h is therefore;

P(63 < x < 75) = P(x < 75) - P(x < 63) = 0.9987 - 0.7257 = 0.273

The probability that the speed of a car is between 63 km/h and 75 km/h is

<u>0.273</u>.

Learn more here:

brainly.com/question/17489087

7 0
2 years ago
What is the anwer of 40+678​
dsp73

Answer:

718

Step-by-step explanation:

just add the two numbers

6 0
3 years ago
Read 2 more answers
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