Given:
M(4,2) is the midpoint of AB and A(-5, -3).
To find:
The coordinates of B.
Solution:
Let the coordinates of point B are (a,b).
Midpoint formula:

M(4,2) is the midpoint of AB and A(-5, -3).


On comparing both sides, we get




And,




Therefore, the coordinates of point B are (13,7).
Answer:
<u>hope it helps...</u>
<u>have a great day!!</u>
5 - 10 x = 3
10 x = 5 - 3
10 x = 2
x = 10 : 5
x = 0.2
The rate is : 0.2 gallons / minute
5 - t * 0.2 = 0
t * 0.2 = 5
t = 5 : 0.2
t = 25 min
Answer: After 25 minutes the container will be empty.
Answer:
Total number of notes is 11.
Step-by-step explanation:
Value is 100 rupees…
5x + 20y = 100 and x + y = 11 are the two equations.
We can simplify…
5x + 20 y - 5x - 5y = 100 - 55 = 45
15y = 45 so y = 3
x = 11 - y = 8
So, we have 8 notes of 5 rupees denomination and 3 notes of 20 rupees denomination.
I hope it helps you.