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3 years ago

Solve: 2(2x + 3) = -6(x + 9)

Mathematics

2 answers:

jek_recluse [69]3 years ago

7 0

Answer:

The answer is x = -6

Step-by-step explanation:

Zina [86]3 years ago

7 0

Answer:

= − 6

Step-by-step explanation:

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PLEASE HELP BEST ANSWER GETS BRAINLIEST URGENT

dybincka [34]

Answer:

-- = y

Step-by-step explanation:

Because it is 25% off, x is divided by 25 to get the price.

For example if x was 100, divide it by 25 you get 75, which is y.

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2 years ago

A home business has an average income of $900.00 per month with a standard deviation of $15.00. If the income in a given month i

Llana [10]

Answer = 2.00

Z score is a statistical that corresponds to the standardization of the regular score to a normal distribution

The formula for Z score is Z = [X - mean ]./ (standard deviation)

Here X = 930.00; mean = 900.00; and standard deviation = 15.00

Then, Z = [930.00 - 900.00] / 15.00 = 30.00 / 15.00 = 2.00

Therefore, your answer is 2.00

Hope I helped :)

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3 years ago

16^3x+8^x+6<br><br>Could you please give me the steps as well for this problem?

BARSIC [14]

Answer:

x = 2

Step-by-step explanation:

$16^{3x} = 8^{x+6} \\2^{4(3x)} = 2^{3(x+6)} -->$ (16 = $2^{4}$ and 8 = $2^{3}$ )

$2^{12x} = 2^{3x+18}$

Since the base number is 2, the exponents must equal each other.

So:

12x = 3x+18

9x = 18

x = 2

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3 years ago

(Pls I need Help) Each figure shown is a constant enlargement of the previous figure. Which rule below could be used to determin

vova2212 [387]

Answer:

I'm here for that the guy who has answer this is correct

Step-by-step explanation:

I had the same answer in got it right

7 0

2 years ago

Customers arrive at a grocery store at an average of 2.1 per minute. Assume that the number of arrivals in a minute follows the

Black_prince [1.1K]

Answer:

a) P(2)=0.270

b) P(X>3)=0.605

c) P=0.410

Step-by-step explanation:

We know that customers arrive at a grocery store at an average of 2.1 per minute. We use the Poisson distribution:

$\boxed{P(k)=\frac{\lambda^k \cdot e^{-\lambda}}{k!}}$

a) In this case: $\lambda=2.1$

$P(2)=\frac{2.1^2 \cdot e^{-2.1}}{2}\\\\P(2)=0.270$

Therefore, the probability is P(2)=0.270.

b) In this case: $\lambda=2\cdot 2.1=4.2$

$P(X>3)=1-P(X\leq 3)\\\\P(X>3)=1-\sum_{x=0}^3 \frac{4.2^x \cdot e^{-4.2}}{x!}\\\\P(X>3)=1-0.395\\\\P(X>3)=0.605$

Therefore, the probability is P(X>3)=0.605.

c) We know that two customers came in in the first minute. That is why we calculate the probability of at least 5 customers entering the other 2 minutes.

In this case: $\lambda=2\cdot 2.1=4.2$

$P(X\geq 5)=1-P(X$

Therefore, the probability is P=0.410.

4 0

3 years ago