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larisa86 [58]
2 years ago
7

What is the solution to 4x + 2 = 6(-2x - 5) ?

Mathematics
2 answers:
exis [7]2 years ago
5 0

Answer:

x= -2

Step-by-step explanation:

4x + 2 = 6(-2x - 5)

Distribute

4x+2 = -12x-30

Add 12x to each side

4x+2+12x = -12x-30+12x

16x+2 = -30

Subtract 2 from each side

16x+2-2=-30-2

16x = -32

Divide by 16

16x/16x = -32/16

x = -2

Luba_88 [7]2 years ago
4 0
The answer is x=-2 !!!!!!!!
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The answer to<br> 6+2(17-13)²
Mamont248 [21]

Answer:

38

Step-by-step explanation:

6 0
3 years ago
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F(x) = 3x + 2 and g(x) = x + 5 g[f(x)] =
Tema [17]

Answer:

f (2x+1)=6x−2

3 0
3 years ago
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Identify the equation in slope-intercept for for the line containing the point (-3,5) and patella to y = -2/3x+5/3
Olegator [25]

Answer:

Y = - 2/3 x + 3

Step-by-step explanation:

y = -2/3x+5/3

Slope = -2/3. .. parallel line has same slope

For (- 3 , 5)

Y intercept = y - my = 5 - ( (-2/3) x (-3) ) = 3

Y = slope x X + y intercept

Y = - 2/3 x + 3

8 0
3 years ago
Andrea, Justin, and Virginia went to an office supply store. Andrea bought 6 pencils, 7 markers, and 8 erasers. Her total was $1
olga2289 [7]

Answer:

x=0.25\,,\,y=1.75\,,\,z=0.25

Step-by-step explanation:

Let x,y,z denotes number of pencils, markers, erasers respectively.

For Andrea:

6x+7y+8z=15.75\,\,\,(i)

For Justin:

6x+8y+5z=16.75\,\,\,(ii)

For Virginia:

5x+5y+7z=11.75\,\,\,(iii)

On subtracting equations (i) and (ii), we get

(6x+7y+8z)-(6x+8y+5z)=15.75-16.75\\-y+3z=-1\\y-3z=1\\y=1+3z

Put y=1+3z in equation (i)

6x+7(1+3z)+8z=15.75\\6x+29z=8.75\,\,\,(iv)

Put y=1+3z in equation (iii)

5x+5(1+3z)+7z=11.75\\5x+22z=6.75\,\,\,(v)

Multiply equation (iv) by 5 and equation (v) by 6 and then subtract both the equations.

5(6x+29z)-6(5x+22z)=5(8.75)-6(6.75)\\13z=3.25\\z=\frac{3.25}{13}=0.25

Put z=0.25 in equation y=1+3z

y=1+3(0.25)=1.75

Put y=1.75\,,\,z=0.25 in equation (i)

6x+7(1.75)+8(0.25)=15.75\\6x+12.25+2=15.75\\6x=1.5\\x=0.25

8 0
3 years ago
Choose the domain for which each function is defined
klemol [59]

Answer:

Part 1) f(x)=\frac{x+4}{x} -----> x\neq 0

Part 2) f(x)=\frac{x}{x+4} ----> x\neq -4

Part 3)  f(x)=x(x+4) ----> All real numbers

Part 4) f(x)=\frac{4}{x^2+8x+16} ----> x\neq -4

Step-by-step explanation:

we know that

The domain of a function is the set of all possible values of x

Part 1) we have

f(x)=\frac{x+4}{x}

we know that

In a quotient the denominator cannot be equal to zero

so

For the value of x=0 the function is not defined

therefore

The domain is

x\neq 0

Part 2) we have

f(x)=\frac{x}{x+4}

we know that

In a quotient the denominator cannot be equal to zero

so

For the value of x=-4 the function is not defined

therefore

The domain is

x\neq -4

Part 3) we have

f(x)=x(x+4)

Applying the distributive property

f*(x)=x^2+4x

This is a vertical parabola open upward

The function is defined by all the values of x

therefore

The domain is all real numbers

Part 4) we have

f(x)=\frac{4}{x^2+8x+16}

we know that

In a quotient the denominator cannot be equal to zero

so

Equate the denominator to zero

x^2+8x+16=0

Remember that

x^2+8x+16=(x+4)^2

(x+4)^2=0

The solution is x=-4

so

For the value of x=-4 the function is not defined

therefore

The domain is

x\neq -4

6 0
3 years ago
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