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2 years ago

What is the solution to 4x + 2 = 6(-2x - 5) ?

Mathematics

2 answers:

exis [7]2 years ago

5 0

Answer:

x= -2

Step-by-step explanation:

4x + 2 = 6(-2x - 5)

Distribute

4x+2 = -12x-30

Add 12x to each side

4x+2+12x = -12x-30+12x

16x+2 = -30

Subtract 2 from each side

16x+2-2=-30-2

16x = -32

Divide by 16

16x/16x = -32/16

x = -2

Luba_88 [7]2 years ago

4 0

The answer is x=-2 !!!!!!!!

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How many cylindrical can of bottles 12 cm high and with 6 cm diameter could be filled from a tank containing 125 liters of deter

Orlov [11]

Answer:

368 cans.

Step-by-step explanation:

Volume of 1 can = π r^2 h.

Here h (height) = 12 and r (radius) = 1/2 * 6 = 3 cm.

So V = π * 3^2 * 12

= 108π cm^3.

The tank hold 125 liters

= 125,000 cm^3, so:

Number of cans that could be filled = 125000/ 108 π

= 368.4.

4 0

2 years ago

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I round to 900 I have twice as many hundreds as ones and all my digits are different but their sums are 18 can someone answer th

stellarik [79]

Answer:

The number of once is 9.1

The number of hundreds is 8.9

Step-by-step explanation:

Given as :

The total of digits having ones and hundreds = 900

The sum of digits = 18

Let The number of ones digit = O

And The number of hundreds digit = H

So, According to question

H + O = 18 .........1

100 × H + 1 × O = 900 ........2

Solving the equation

( 100 × H - H ) + ( O - O ) = 900 - 18

Or, 99 H + 0 = 882

Or , 99 H = 882

∴ H = $\frac{882}{99}$

I.e H = 8.9

Put the value of H in eq 1

So, O = 18 - H

I.e O = 18 - 8.9

∴ O = 9.1

So, number of once = 9.1

number of hundreds = 8.9

Hence The number of once is 9.1 and The number of hundreds is 8.9

Answer

4 0

2 years ago

PLS HURRY!

Ratling [72]

A is the correct answer 3 terms and a degree of 9:)

4 0

2 years ago

Determine (a) the slope of the line parallel to the line whose slope is m=2 and (b) the slope of the line perpendicular to the l

kotykmax [81]

Answer:

(b) $\displaystyle -\frac{1}{2} = m$

(a) $\displaystyle 2 = m$

Step-by-step explanation:

Perpendicular Lines have OPPOSITE MULTIPLICATIVE INVERSE RATE OF CHANGES [SLOPES], whereas Parallel Lines have SIMILAR RATE OF CHANGES [SLOPES].

I am joyous to assist you anytime.

7 0

2 years ago

1) What radius of a circle is required to inscribe an equilateral triangle with an area of 15.588 in2 and an altitude of 5.196 i

Andrej [43]

We know that
the distance from the centroid of the triangle to one of the vertices is the radius of the circle required to inscribe an equilateral triangle.

[distance centroid of the triangle to one of the vertices]=(2/3)*h
h=the altitude of the equilateral triangle-----> 5.196 in
so
[distance centroid of the triangle to one of the vertices]=(2/3)*5.196
[distance centroid of the triangle to one of the vertices]=3.464 in----> 3.5 in

the radius is equal to the distance of the centroid of the triangle to one of the vertices
hence
the radius is 3.5 in

the answer is
the radius is 3.5 in

8 0

2 years ago

Read 2 more answers