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4 years ago

REAL SQUARE ROOTS OF 36/49

Mathematics

2 answers:

Goryan [66]4 years ago

8 0

One is 6/7
Can you tell me what the other one is?

PolarNik [594]4 years ago

4 0

The square roots of 36 and 49 is 6 and 7.
36 = 7^2
49= 7^2

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A relation is a function if _____.

valentina_108 [34]

... <span>exactly one output for each input

This is an important concept; be certain that you understand it.

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8 0

3 years ago

what angle is half of its supplement; the measure of one angle is 15 less than half the measurement of its supplement; complemen

Delvig [45]

So one angle is of measurement 130 degree and the other angle is of measurement 50 degree.

<h3>What are angles?</h3>

When two rays are linked at their ends, they create an angle in geometry. The sides or arms of the angle are what are known as these rays.

When two lines meet at a point, an angle is created.

An "angle" is the measurement of the "pening" between these two rays. It is symbolized by the character. The circularity or rotation of an angle is often measured in degrees and radians.

Angles are a common occurrence in daily life.

Angles are used by engineers and architects to create highways, structures, and sports venues.

According to our question-

One angle's measurement is 15 less than its supplement's measurement.

Let's say that the supplement angle is measured in degrees.

So the measurement of the other angle is

And the sum of the measurement of supplementary angles is 180.

Multiplying both sides by 2

Therefore, one angle is 130 degrees in length and the other is 50 degrees.

learn more about angles click here:

brainly.com/question/25716982

#SPJ4

4 0

1 year ago

Find (f - g)(x) if f(x) = x2 - x - 6 and g(x) = 2x2 - 3x + 4

Nadya [2.5K]

For this question we just have to re-substitute the expressions for their respective functions by assigning them in a plausible condition for two functions. Here, the first function of "x" is subtracted by a second function of "x". The expressions are assigned according to the first and second function expressions in each case or condition.

All we have to do is distribute the parentheses for second expression to deploy positive addition between 2x^2 and 3x. Furthermore grouping all the like terms to get the required answer to this query. So, let me express this via LaTeX interpreter equation editor for a better understanding and clear all the doubts for these forms of queries.

$\mathbf{Since, \: \: f(x) = x^2 - x - 6}$

$\mathbf{\therefore \quad \Big(x^2 - x - 6 - g(x) \Big) \: (x)}$

$\mathbf{Since, \: \: g(x) = 2x^2 - 3x + 4}$

$\mathbf{\therefore \quad x^2 - x - 6 - (2x^2 - 3x + 4)}$

$\mathbf{x^2 - x - 6 - (2x^2) - (- 3x) - (+ 4)}$

$\mathbf{x^2 - x - 6 - 2x^2 + 3x - 4}$

$\mathbf{x^2 - 2x^2 - x + 3x - 6 - 4}$

$\mathbf{x^2 - 2x^2 + 2x - 6 - 4}$

$\mathbf{- x^2 + 2x - 6 - 4}$

$\boxed{\mathbf{\underline{Required \: \: Answer: \: - x^2 + 2x - 10}}}$

Hope it helps.

6 0

3 years ago

Solve the proportion below. 7/x = 19/144

timofeeve [1]

Answer:

$\boxed{\boxed{\tt B)\: 42}}$

<h3>Step-by-step explanation:</h3>

$\tt \cfrac{7}{x}=\cfrac{19}{114}$

<u>Cross multiply:</u>

(Multiply the numerator in the first fraction times the denominator in the second fraction, then multiply the numerator of the second fraction times the number in the denominator of your first fraction.)

$\longmapsto\tt 798=x\times \:19$