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4 years ago

REAL SQUARE ROOTS OF 36/49

Mathematics

2 answers:

Goryan [66]4 years ago

8 0

One is 6/7
Can you tell me what the other one is?

PolarNik [594]4 years ago

4 0

The square roots of 36 and 49 is 6 and 7.
36 = 7^2
49= 7^2

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A line has a y-intercept and a slope of 0. What is it’s equation in slope-intercept form ?

PSYCHO15rus [73]

Answer:

y = 0

Step-by-step explanation:

y = mx + b so if m = 0 then x = 0 and if be is also 0 then that entire side of the equation is 0. Meaning that y = 0

5 0

3 years ago

What is the rate of change for a linear function that passes through the points (8, -10) and (-6, 14)

Anna71 [15]

Answer: $m=-1.714$

Step-by-step explanation:

By definition, the slope of the line is described as "Rate of change".

You need to use the following formula to calcualte the slope of the line;

$m=\frac{y_2-y_1}{x_2-x_1}$

In this case you know that the line passes through these two points: (8, -10) and (-6, 14).

Then, you can say that:

$y_2=-10\\y_1=14\\\\x_2=8\\x_1=-6$

Knowing these values, you can substitute them into the formula for calculate the slope of a line:

$m=\frac{-10-14}{8-(-6)}$

Finally, you must evaluate in order to find the slope of this line. You get that this is:

$m=\frac{-24}{8+6}\\\\m=\frac{-24}{14}\\\\m=-\frac{12}{7}\\\\m=-1.714$

8 0

3 years ago

If 180° < α < 270°, cos⁡ α = −817, 270° < β < 360°, and sin⁡ β = −45, what is cos⁡ (α + β)?

eduard

Answer:

$cos(\alpha+\beta)=-\frac{84}{85}$

Step-by-step explanation:

we know that

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

Remember the identity

$cos^{2} (x)+sin^2(x)=1$

step 1

Find the value of $sin(\alpha)$

we have that

The angle alpha lie on the III Quadrant

The values of sine and cosine are negative

$cos(\alpha)=-\frac{8}{17}$

Find the value of sine

$cos^{2} (\alpha)+sin^2(\alpha)=1$

substitute

$(-\frac{8}{17})^{2}+sin^2(\alpha)=1$

$sin^2(\alpha)=1-\frac{64}{289}$

$sin^2(\alpha)=\frac{225}{289}$

$sin(\alpha)=-\frac{15}{17}$

step 2

Find the value of $cos(\beta)$

we have that

The angle beta lie on the IV Quadrant

The value of the cosine is positive and the value of the sine is negative

$sin(\beta)=-\frac{4}{5}$

Find the value of cosine

$cos^{2} (\beta)+sin^2(\beta)=1$

substitute

$(-\frac{4}{5})^{2}+cos^2(\beta)=1$

$cos^2(\beta)=1-\frac{16}{25}$

$cos^2(\beta)=\frac{9}{25}$

$cos(\beta)=\frac{3}{5}$

step 3

Find cos⁡ (α + β)

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

we have

$cos(\alpha)=-\frac{8}{17}$

$sin(\alpha)=-\frac{15}{17}$

$sin(\beta)=-\frac{4}{5}$

$cos(\beta)=\frac{3}{5}$

substitute

$cos(\alpha+\beta)=-\frac{8}{17}*\frac{3}{5}-(-\frac{15}{17})*(-\frac{4}{5})$

$cos(\alpha+\beta)=-\frac{24}{85}-\frac{60}{85}$

$cos(\alpha+\beta)=-\frac{84}{85}$

4 0

3 years ago

-3 1/2 - 2 1/3 explained

lakkis [162]

The answer is 5 5/6 simplified to the max.

rewrite the equation with separated parts

-3 1/2 - 2 1/3

-3 - 2 = -5

-1/2 - 1/3? u need to find the LEAST common denominator

-3/6 - 2/6 = -5/6

how did I get 6?

Rewriting input as fractions if necessary:
1/2, 1/3

For the denominators (2, 3) the least common multiple (LCM) is 6.

Therefore, the least common denominator (LCD) is 6.

Now lastly combine them total and its -5 - 5/6 = -5 5/6.

5 0

3 years ago

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What is <br><br> 6/1 divided by 3/4<br><br> if i put it in the wrong way.. then SORRY

Pani-rosa [81]

The answer is 8

Step by step:

6x4/1x3 =

24/3

(24/3)/(3/3) = 8

5 0

3 years ago

Read 2 more answers