Answer:
81 times the original size
Step-by-step explanation:
AA0ktA=3A0=?=?=25hours=A0ekt
Substitute the values in the formula.
3A0=A0ek⋅25
Solve for k. Divide each side by A0.
3A0A0=e25k
Take the natural log of each side.
ln3=lne25k
Use the power property.
ln3=25klne
Simplify.
ln3=25k
Divide each side by 25.
ln325=k
Approximate the answer.
k≈0.044
We use this rate of growth to predict the number of bacteria there will be in 100 hours.
AA0ktA=3A0=?=ln325=100hours=A0ekt
Substitute in the values.
A=A0eln325⋅100
Evaluate.
A=81A0
At this rate of growth, we can expect the population to be 81 times as large as the original population.
Answer:
D i believe
Step-by-step explanation: hoped this helps
The first thing to take into account is that the probability of getting any of the six numbers of the dice after rolling it is the same and that probability is 1/6. Here we are being asked about the probability of getting a 1 or a 4 or a 5. In order to find it we need to define which are our favourable cases. Favourable cases are the results we want to get when we roll the dice so getting a 1, a 4 or a 5 are all favourable cases. All the other possible outcomes are unfovourable cases: getting a 2, a 3 or a 6. So we have 3 favourable and 3 unfavourable cases. Adding them we know that the total amount of cases is 6. The probability we are looking for (i'm going to call it P) is given by these quantities I defined:

So the probability written as a simplified fraction is 1/2.