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Anastasy [175]
3 years ago
10

What is 6/1 divided by 3/4 if i put it in the wrong way.. then SORRY

Mathematics
2 answers:
Pani-rosa [81]3 years ago
5 0

The answer is 8

Step by step:

6x4/1x3 =

24/3

(24/3)/(3/3) = 8

timama [110]3 years ago
5 0

\bold{Hey\ there!}

  • \bold{\frac{6}{1}\div\frac{3}{4}}
  • \bold{Flip\ the\ equation\ around:} \bold{\frac{3}{4} \rightarrow to\ \frac{4}{3}}
  • \bold{New\ problem:\frac{6}{1}\div\frac{4}{3}}
  • \bold{Multiply:numerator\&numerator\ \leftrightarrow denominator\&denominator}
  • \bold{\frac{6\times4}{1\times3}}
  • \bold{6\times4=24}
  • \bold{3\times1=3}
  • \bold{numerator\rightarrow24}
  • \bold{denominator\rightarrow3}
  • \bold{\frac{24\div3}{3\div3}}
  • \bold{24\div3=8}
  • \boxed{\boxed{\bold{Answer:8}}}\checkmark

\bold{Good\ luck\ on\ your\ assignment\ \&} \bold{enjoy\ your\ day!}

~\frak{LoveYourselfFirst:)}

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Assume that advanced students average 93% on an achievement test and regular students averaged 75%. If 100 advanced students and
Lemur [1.5K]
Average (mean) = (sum of all the data) / (# of data)

sum of all the data = (average)(# of data)

Thus for 100 students with an average of 93,
sum of all data = (93)(100) = 9300

and for 300 students with an average of 75,
sum of all data = (75)(300) = 22500

Therefore you would expect the overall average to be
(9300 + 22500) / (100 + 300) = 79.5 %

Now if there are x # of advanced students and y # of regular students, then

x + y = 90 (total # of students) and 93x + 75y = 87(x + y) (overall average)

The second equation can be simplified to x - 2y = 0

Subtracting the two equations yields

x = 60 and y = 90

Therefore you would need 60 advanced and 30 regular students.
7 0
3 years ago
Use the distributive property to simplify the expression: -4(4x + 3) + (7x - 2)
Elodia [21]
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7 0
3 years ago
How do you solve -1x+20 is greater than -7+35
rusak2 [61]

\huge\fbox{Hello~there!}

Let's solve this inequality!

\rm{-x+20>-7+35

What can we do to solve this inequality? Well, first of all, we can add -7 and 35:

\rm{-x+20>28

Now, move 20 to the right, using the opposite operation:

\rm{-x>28-20

Subtract:

\rm{-x>8

Divide both sides by -1 to isolate x:

\rm{x (Answer)

_____________

<em>Additional comment</em>

When we divide both sides of an inequality by a negative number, we flip the inequality sign.

____________

I hope you find it helpful.

Feel free to ask if you have any questions.

\bf{-MistySparkles^**^*

3 0
2 years ago
If sine of x equals 1 over 2, what is cos(x) and tan(x)?
emmasim [6.3K]
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5 0
3 years ago
Solve 2x+ 3=7<br> please ​
blondinia [14]

2x+3=7

2x+3-3=7-3

Whenever moving a number to the other side you have to change the sign .

2x= 4

x=2

7 0
3 years ago
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