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dolphi86 [110]
4 years ago
15

Friends height is close to 160 centimeters what is your friends height close to in meters

Mathematics
2 answers:
r-ruslan [8.4K]4 years ago
8 0
Their height is 1.6 meters
aalyn [17]4 years ago
4 0
Your friend's height in centimeters is about 160, and 1 meter is equal to exactly 100 centimeters. So, your friend's height would be about 1.6 meters.
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Which of the following is NOT true about a rhombus?
Naily [24]

Answer:

Which of the following is NOT true about a rhombus?

options:

lines of symmetry are the perpendicular bisectors

lines of symmetry are the diagonals

a rhombus has four congruent sides

a rhombus is a quadrilateral

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3 years ago
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If a car travels 55 miles per hour how far will it travel in half an hour​
dimulka [17.4K]

Answer:

27.5

Step-by-step explanation:

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3 years ago
Calc help pretty please
Gre4nikov [31]

Answer:

A.  77.4

Step-by-step explanation:

<u>Linear approximation formula</u>

L(x)=f(a)+f'(a)(x-a)

Given function:

f(x)=(x+1)^2

\boxed{\begin{minipage}{5.4 cm}\underline{Chain Rule for Differentiation}\\\\If  $y=f(u)$  and  $u=g(x)$  then:\\\\$\dfrac{\text{d}y}{\text{d}x}=\dfrac{\text{d}y}{\text{d}u}\times \dfrac{\text{d}u}{\text{d}x}$\\\end{minipage}}

\boxed{\begin{minipage}{5 cm}\underline{Differentiating $x^n$}\\\\If  $y=x^n$, then $\dfrac{\text{d}y}{\text{d}x}=xn^{n-1}$\\\end{minipage}}

\boxed{\begin{minipage}{4 cm}\underline{Differentiating $ax$}\\\\If  $y=ax$, then $\dfrac{\text{d}y}{\text{d}x}=a$\\\end{minipage}}

Use the chain rule to differentiate the function.

\textsf{Let }\:y=u^2\:\textsf{ where }u=(x+1)

Differentiate the two parts separately:

  y=u^2 \implies \dfrac{\text{d}y}{\text{d}u}=2u

  u=x+1 \implies \dfrac{\text{d}u}{\text{d}x}=1

Put everything back into the chain rule formula:

\begin{aligned} \implies \dfrac{\text{d}y}{\text{d}x} & =2u \times 1\\ & = 2u \\ & = 2(x+1)\\ & = 2x+2 \end{aligned}

\textsf{Therefore, }\:f'(x)=2x+2..

The <u>linear approximation</u> at a = 8 is:

\begin{aligned}L(x) & =f(a)+f'(a)(x-a)\\\\\implies L(x) & = f(8)+f'(8)(x-8)\\& = (8+1)^2+(2(8)+2)(x-8)\\& = 81+18(x-8)\\& = 18x-63\end{aligned}

Finally, substitute x = 7.8 into the <u>linear approximation equation</u>:

\begin{aligned}\implies L(7.8) & =18(7.8)-63\\& = 140.4-63\\& = 77.4\end{aligned}

4 0
2 years ago
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Klio2033 [76]

Answer:

see below  PLEASE GIVE BRAINLIEST

Step-by-step explanation:

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Answer:

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3 years ago
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