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RideAnS [48]
3 years ago
10

Which equation is the inverse of y=2x^2-8

Mathematics
2 answers:
dmitriy555 [2]3 years ago
7 0
To get the inverse, we should swap the x- and y-variables, then solve for y. Swapping the variables gives the equation: x=2y^2-8
Solving for y:
x+8=2y^2 \\ \frac{x+8}{2}=y^2 \\ y=\sqrt{\frac{x+8}{2}}


shusha [124]3 years ago
4 0

Step-by-step explanation:

In order to get the inverse of equation, we will interchange the variables and solve for x and y as follows.

             y = 2x^{2} - 8

whereas,  y + 8 = 2x^{2}

    or              x = \sqrt{\frac{y+8}{2}}

Now, on interchanging the variable we will get the equation as follows.

               x = 2y^{2} - 8

               x + 8 = 2y^{2}

                     y = \sqrt{\frac{x+8}{2}}


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Mnenie [13.5K]

Answer:

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Step-by-step explanation:

We want to determine the result of the quotient: \dfrac{3x^3+x-11}{x+1}

We follow the procedure of long division which is set out int he table below.

\left|\begin{array}{c|c}&3x^2-3x+4\\-----&-----\\x+1&3x^3+x-11\\Subtract&-(3x^3+3x^2)\\&------\\&-3x^2+x-11\\Subtract&-3x^2-3x\\&------\\&4x-11\\Subtract&4x+4\\&------\\&-15\end{array}\right|

Therefore:

\dfrac{3x^3+x-11}{x+1}=3x^2-3x+4-\dfrac{15}{x+1}

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