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Ronch [10]
3 years ago
15

At which layer of the osi model is the entire message referred to as the payload

Computers and Technology
1 answer:
erik [133]3 years ago
6 0

I guess the correct answer is application

An applicatiοn layеr is an abstractiοn layеr that spеcifiеs thе sharеd cοmmunicatiοns prοtοcοls and intеrfacе mеthοds usеd by hοsts in a cοmmunicatiοns nеtwοrk. Thе applicatiοn layеr abstractiοn is usеd in bοth οf thе standard mοdеls οf cοmputеr nеtwοrking: thе Intеrnеt Prοtοcοl Suitе (TCP/IP) and thе ΟSI mοdеl. Althοugh bοth mοdеls usе thе samе tеrm fοr thеir rеspеctivе highеst lеvеl layеr, thе dеtailеd dеfinitiοns and purpοsеs arе diffеrеnt.

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When programming, the word "execute" means which of these?
Inga [223]

Answer:

to run!

Explanation:

hope this is helpful!

7 0
3 years ago
PASSAGE: The picnic had been scheduled for weeks in advance. The Morris family was looking forward to some fun and relaxation wi
Mekhanik [1.2K]

Answer:

B) The sky began to darken and rumble.

Explanation:

B) The sky began to darken and rumble.

It seems they have arranged it big. Hence, the money is not a problem. Any number of people can be invited,

The problem was certainly that the rain was about to come as sky turned dark and rumble. And hence, this answer as its what created tension.

7 0
3 years ago
Programming challenge description: Given a string comprising just of the characters (,),{,},[,] determine if it is well-formed o
nadezda [96]

Answer:

Employing Java language,

Explanation:

//for using stack data structure

import java.util.Stack;

//class definition

public class BracketMatch {

   //function to find the string is well formed or not

   public static boolean isWellFormed(String str) {

       //variable to store the character value

       char ch;

       //check if the first character itself is the end of the brackets

       if (str.charAt(0) == ')'||str.charAt(0) =='}'||str.charAt(0) ==']')

           return false;

       //creating a stack of character type

       Stack<Character> stack = new Stack<Character>();

       //iterating through the characters in string

       for(int i=0; i < str.length(); i++) {

           //storing the current character from the string in the variable

           ch = str.charAt(i);

           if(ch == '('||ch=='{'||ch=='[')

               //if the character is starting of the brackets push it into stack

               stack.push(ch);

           else if(ch == ')')

               //if it is closing bracket and the stack is empty then the string is not well formatted

               if(stack.empty())

                   return false;

               else if(stack.peek() == '(')

                   stack.pop();

               else

                   return false;

           else if(ch == '}')

               if(stack.empty())

                   return false;

               else if(stack.peek() == '{')

                   stack.pop();

               else

                   return false;

       }

       //returning the stack content, if the string will be well formed the stack would be empty

       //after all the operations

       return stack.empty();

   }

   //main method

   public static void main(String[] args) {

       //calling function to find if the string is welll formatted or not

       System.out.println(isWellFormed("{}"));

       //calling function to find if the string is welll formatted or not

       System.out.println(isWellFormed("([)]"));

   }

}

5 0
4 years ago
All of the following are forms of verbal communication except
Radda [10]
B. hand gestures
these are not verbal.
4 0
3 years ago
Read 2 more answers
This exercise asks you to write a program that tests some of the built-in subroutines for working with Strings. The program shou
klasskru [66]

Answer:

Java.

Explanation:

// Get user input

System.out.print("Please enter your first name and last name separated by a space: ");

userInput = TextIO.getln();

// Find index of space character

int spaceIndex = userInput.indexOf(' ');

// Extract first and last name using space character index

// I have used length() method to get length of string userInput.

String firstName = userInput.substring(0, spaceIndex-1);

String lastName = userInput.substring(spaceIndex+1, userInput.length()-1);

// Print the required statements

System.out.print("Your first Name is %s, which has %d characters%n", firstName, firstName.length());

System.out.print("Your last Name is %s, which has %d characters%n", lastName, lastName.length());

// I have used space character Index to get the Initial of last name

System.out.print("Your initials are %s%s", firstName.substring(0,0), lastName.substring(spaceIndex+1, spaceIndex+1));

5 0
3 years ago
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