1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Harman [31]
3 years ago
6

What does it mena when they say "all germs are germs"

Computers and Technology
1 answer:
KiRa [710]3 years ago
7 0

Answer:it means that germs are germs germs are reproductive they split apart from one another to create more germs.

Explanation:

You might be interested in
In Java, it is possible to create an infinite loop out of while and do loops, but not for-loops. true or false
soldier1979 [14.2K]

Answer:

False is the correct answer for the above question.

Explanation:

  • In java programming language or any other programming language, any loop can be infinite.
  • It is because the infinite loop is called for that loop which is not run in a finite number of times.
  • The loop is used to repeat some lines in a finite number of times. Any loop has three things- first is the initial value which tells the loop to start, The second is the condition check which states when the loop will stop and the third is an operation which directs some variable, so that the condition may be false after some finite amount of time.
  • If the condition will not false in any iteration of the loop, then the loop can proceed for an infinite amount of time.
  • The above-question states that the while loop and do while loop can be infinite which is a true statement.
  • But it also states that the 'for' loop can not be infinite which is not a correct statement which is described above. Hence false is the correct answer to the above question.
8 0
3 years ago
Write a program that use a switch statement whose controlling expression is the variable area code. If the value of area_code is
scZoUnD [109]

Answer:

Table for Area codes are not missing;

See Attachment for area codes and major city I used

This program will be implemented using c++ programming language.

// Comments are used for explanatory purposes

// Program starts here

#include <iostream>

using namespace std;

int main( )

{

// Declare Variable area_code

int area_code;

// Prompt response from user

cout<<Enter your area code: ";

cin<<"area_code;

// Start switch statement

switch (area_code) {

// Major city Albany has 1 area code: 229...

case 229:

cout<<"Albany\n";

break;

// Major city Atlanta has 4 area codes: 404, 470 678 and 770

case 404:

case 470:

case 678:

case 770:

cout<<"Atlanta\n";

break;

//Major city Columbus has 2 area code:706 and 762...

case 706:

case 762:

cout<<"Columbus\n";

break;

//Major city Macon has 1 area code: 478...

case 478:

cout<<"Macon\n";

break;

//Major city Savannah has 1 area code: 912..

case 912:

cout<<"Savannah\n";

break;

default:

cout<<"Area code not recognized\n";

}

return 0;

}

// End of Program

The syntax used for the above program is; om

6 0
4 years ago
Complete the sentence.<br> The IP protocol creates and addresses packets at the _____ layer.
brilliants [131]
Addresses packets at the internet layer
4 0
3 years ago
Read 2 more answers
Create an array of numbers filled by the random number generator. (value = (int)(Math.random() * 100 + 1);) Print the array and
Y_Kistochka [10]

Answer:

Explanation:

the following is the code to run this (JAVA)

MeanStandardDev.java

import java.util.Random;

import java.util.Scanner;

public class MeanStandardDev {

public static void main(String[] args) {

// Declaring variables

int N;

double lower, upper, min, max, mean, stdDev;

/*

* Creating an Scanner class object which is used to get the inputs

* entered by the user

*/

Scanner sc = new Scanner(System.in);

// Getting the input entered by the user

System.out.print(" How many Random Numbers you want to generate :");

N = sc.nextInt();

System.out.print("Enter the Lower Limit in the Range :");

lower = sc.nextDouble();

System.out.print("Enter the Upper Limit in the Range :");

upper = sc.nextDouble();

// Creating Random class object

Random rand = new Random();

double nos[] = new double[N];

// this loop generates and populates 10 random numbers into an array

for (int i = 0; i < nos.length; i++) {

nos[i] = lower + (upper - lower) * rand.nextDouble();

}

//calling the methods

min = findMinimum(nos);

max = findMaximum(nos);

mean = calMean(nos);

stdDev = calStandardDev(nos, mean);

//Displaying the output

System.out.printf("The Minimum Number is :%.1f\n",min);

System.out.printf("The Maximum Number is :%.1f\n",max);

System.out.printf("The Mean is :%.2f\n",mean);

System.out.printf("The Standard Deviation is :%.2f\n",stdDev);

}

//This method will calculate the standard deviation

private static double calStandardDev(double[] nos, double mean) {

//Declaring local variables

double standard_deviation=0.0,variance=0.0,sum_of_squares=0.0;

/* This loop Calculating the sum of

* square of eeach element in the array

*/

for(int i=0;i<nos.length;i++)

{

/* Calculating the sum of square of

* each element in the array    

*/

sum_of_squares+=Math.pow((nos[i]-mean),2);

}

//calculating the variance of an array

variance=((double)sum_of_squares/(nos.length-1));

//calculating the standard deviation of an array

standard_deviation=Math.sqrt(variance);

return standard_deviation;

}

//This method will calculate the mean

private static double calMean(double[] nos) {

double mean = 0.0, tot = 0.0;

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Calculating the sum of all the elements in the array

tot += nos[i];

}

mean = tot / nos.length;

return mean;

}

//This method will find the Minimum element in the array

private static double findMinimum(double[] nos) {

double min = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] < min)

min = nos[i];

}

return min;

}

//This method will find the Maximum element in the array

private static double findMaximum(double[] nos) {

double max = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] > max)

max = nos[i];

}

return max;

}

}

the OUTPUT should give;

How many Random Numbers you want to generate :10

Enter the Lower Limit in the Range :1.0

Enter the Upper Limit in the Range :10.0

The Minimum Number is :1.1

The Maximum Number is :9.9

The Mean is :6.30

The Standard Deviation is :2.98

cheers i hope this helps!!!

4 0
3 years ago
Arrange the steps in the process of manually installing software.
Ahat [919]

The correct sequence is: 5,3,1,4,2

When you are installing software on your computer you need to first open the CD-ROM and then insert the installation CD into the CD-ROM. If the contents of the CD opens, click on the executable file to start the wizard, and then follow the prompts in the wizard. Finally, you often need to reboot your computer after installing a new program.

5 0
3 years ago
Other questions:
  • Jeremy Bridges is an executive for Green Web Designs, where his primary role is to ensure the security of business systems and d
    6·1 answer
  • Heatsinks used to protect cpus in computers from overheating, are shaped so that their surface area is very large. why is that?
    5·1 answer
  • Clip art, by default, is formatted as a(n) ____, which cannot be moved to a precise location on a page.
    14·1 answer
  • A DSLR camera is made up of two parts. They are
    13·2 answers
  • Walking paths across the part is represented by the equation why equals -4x - 6​
    9·1 answer
  • 7. What is the school campus’s setting<br> the school is sanford
    6·2 answers
  • Which statement describes borders and shading ?
    13·1 answer
  • The program is to be answered in Java Programming not C++ Please answer the following: Modify the BarChart program to accept the
    6·1 answer
  • Lesson 2.7 Code Practice #2
    13·1 answer
  • To obtain your class E learner license, youll need too _
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!