4 cos² x - 3 = 0
4 cos² x = 3
cos² x = 3/4
cos x = ±(√3)/2
Fixing the squared cosine doesn't discriminate among quadrants. There's one in every quadrant
cos x = ± cos(π/6)
Let's do plus first. In general, cos x = cos a has solutions x = ±a + 2πk integer k
cos x = cos(π/6)
x = ±π/6 + 2πk
Minus next.
cos x = -cos(π/6)
cos x = cos(π - π/6)
cos x = cos(5π/6)
x = ±5π/6 + 2πk
We'll write all our solutions as
x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k
Answer:
Step-by-step explanation:
4
Answer:
should be 63
Step-by-step explanation:
Answer: 10
Step-by-step explanation:
In a right angle triangle
Hypothenus ^2= opposite ^2+ adjacent ^2
According to a diagram below
Hypothenus =15
Opposite =?
Adjacent =11
Substitute for the values
15^2=11^2+opp^2
Opp^2=15^2-11^2
0pp^2= 225-121
Opp2=104
Opp= square root of 104
Opp= 10.2
Opp= ~10
Answer:
D: c^2 + (x+5)^2 = 841
Step-by-step explanation:
edge :)