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elena-14-01-66 [18.8K]
3 years ago
11

Solve ? -4-4(-x-1)=-4(6+2x)​

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
7 0

-4-4(-x-1)=-4(6+2x)\\\\-4+4x+4=-24-8x\\\\4x=-24-8x \ \ /+8x\\\\12x=-24 \ \ /:12\\\\\huge\boxed{x=-2}

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702 fish

Step-by-step explanation:

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Mrs. Reed collects shells. Each shell in her collection weighs about 4 ounces. Her collection weighs about 12 pounds in all. Abo
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2 years ago
What is the equation of a line, in general form, that passes through the point (1, -2) and has a slope of 1/3.
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5 0
2 years ago
Read 2 more answers
A trough of water is 20 meters in length and its ends are in the shape of an isosceles triangle whose width is 7 meters and heig
Vaselesa [24]

Answer:

a) Depth changing rate of change is 0.24m/min, When the water is 6 meters deep

b) The width of the top of the water is changing at a rate of 0.17m/min, When the water is 6 meters deep

Step-by-step explanation:

As we can see in the attachment part II, there are similar triangles, so we have the following relation between them \frac{3.5}{10} =\frac{a}{h}, then a=0.35h.

a) As we have that volume is V=\frac{1}{2} 2ahL=ahL, then V=(0.35h^{2})L, so we can derivate it \frac{dV}{dt}=2(0.35h)L\frac{dh}{dt} due to the chain rule, then we clean this expression for \frac{dh}{dt}=\frac{1}{0.7hL}\frac{dV}{dt} and compute with the knowns \frac{dh}{dt}=\frac{1}{0.7(6m)(20m)}2m^{3}/min=0.24m/min, is the depth changing rate of change when the water is 6 meters deep.

b) As the width of the top is 2a=0.7h, we can derivate it and obtain \frac{da}{dt}=0.7\frac{dh}{dt}  =0.7*0.24m/min=0.17m/min The width of the top of the water is changing, When the water is 6 meters deep at this rate

8 0
3 years ago
6(33 - w) = 90 solve for w entre your answer in the box w =
aliina [53]

Answer:

w = 18

Step-by-step explanation:

6(33 - w) = 90

33 - w = 15

-w = -18

w = 18

5 0
2 years ago
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