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dsp73
2 years ago
12

One of the legs of a right triangle measures 4 cm and its hypotenuse measures 5 cm. Find the measure of the other leg. If necess

ary, round to the nearest tenth.
Mathematics
1 answer:
Zigmanuir [339]2 years ago
8 0
A^2 + b^2 = c^2
4^2 + b^2 = 5^2
16 + b^2 = 25. -16
B^2 = 9
Square root of 9 = 3
B = 3

The other leg is 3cm
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15 liters increased by 60%
kicyunya [14]
15 liters increased by 60% is 24 liters.
8 0
3 years ago
The longest side in a right triangle is 24 cm, and the second longest side is 20 cm. Find the length of the shortest side
harkovskaia [24]

Answer:

13.3 cm

Step-by-step explanation:

Apply the Pythagorean Theorem:

hyp² = (2nd longest side)² + (shortest side)².  Here the numbers are:

(24 cm)² = (20 cm)² + (shortest side)², or

576 - 400 = 176 = hyp²

Taking the square root of both sides, we get (shortest side) = 13.3 cm

5 0
3 years ago
Read 2 more answers
Order the numbers from least to greatest. 3 63/80 , 3 1/5 , 3 11/20
gregori [183]

Let's compare apples to apples and oranges to oranges: convert each given proper fraction into its decimal counterpart:

3 63/80 => 3 .788 approx.

3 1/5 => 3.2

3 11/20 => 3.55

It's now an easy matter to arrange these numbers from least to greatest:

3.2, 3.55, 3.79, or

3 1/5, 3 11/20, 3 63/80


7 0
3 years ago
RS = 4x – 9, ST = 19, RT = 80 – 14<br><br> Equation:<br><br> 82 – 14<br><br> RS<br><br> RT
algol13

Step-by-step explanation:

The expressions are not properly written

Given

RS = 4x – 9

ST = 19

RT = 8x – 14

Based on the given parameters, the addition postulate below is true

RS+ST = RT

Substitute

4x-9+19 = 8x-14

collect like terms

4x-8x = -14-19+9

-4x = -33+9

-4x = -24

x = -24/-4

x = 6

Get RS:

RS = 4x-9

RS = 4(6)- 9

RS = 24-9

RS = 15

Get RT:

RT = 8x - 14

RT = 8(6)-14

RT = 48-14

RT = 34

4 0
3 years ago
Solve triangle ABC, when A= 6, B=10 and c=12
valentinak56 [21]
Use cosine rule,

cos(A)=(b^2+c^2-a^2)/(2bc)
=(10^2+12^2-6^2)/(2*10*12)
=13/15
A=29.926 degrees.................................(A)

cos(B)=(c^2+a^2-b^2)/(2ca)
=(12^2+6^2-10^2)/(2*12*6)
=5/9
B=56.251 degrees.................................(B)

cos(C)=(a^2+b^2-c^2)/(2ab)
=(6^2+10^2-12^2)/(2*6*10)
=-1/15
C=93.823 degrees.................................(C)

Check:29.926+56.251+93.823=180.0 degrees....ok
5 0
3 years ago
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