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Solnce55 [7]
4 years ago
8

Vladimir says that the equation of the line that passes through points above Robyn says that the line passes through the points

above Who is correct?​

Mathematics
1 answer:
aleksley [76]4 years ago
8 0

Answer:

Both are correct

Step-by-step explanation:

The Line has the following equation: y= 1+4/5 x

So we need to know which points: (-5,-3) and (10,9), (-10,-7). (-15, -11) are part of the line

For instances, lest start by evaluating (-15,-11) in y=1+4/5 x

this leaves us to the following operation: -11=1+4/5 * (-15)

-11=1-4*3 resulting in a equality -11=-11, this point does belong to the line

Repeat the above for all of the remaining points and you will get the same conclusion, that is we Vladimir and Robyn are correct.

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You have 4 reindeer, Bloopin, Balthazar, Gloopin, and Prancer, and you want to have 3 fly your sleigh. You always have your rein
Ivahew [28]

Answer:

P43=4!(4–3)!=241=24

Step-by-step explanation:

There are four choices you can make for the lead reindeer. For each possible choice, there are then three remaining you can choose to fly second, making 4×3=12 choices for the lead pair. For each possible choice there are two remaining reindeer to take up the back position, making 12×2=24 choices for the team of three.

This type of problem is called a permutation problem, and we write Pnr for the number of ways of choosing r items from n possibilities when the order of the items matters. In this case we are choosing 3 reindeer from 4 possibilities, and the order they appear in the flying line does matter, so the answer we want is P43. The general formula is Pnr=n!(n−r)!. For the answer we are looking for we therefore have:

P43=4!(4–3)!=241=24

7 0
4 years ago
A line passes through (-9,-5) and (2,-4)
zlopas [31]

The point-slope form of a line:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-9, -5) and (2, -4). Substitute:

m=\dfrac{-4-(-5)}{2-(-9)}=\dfrac{1}{11}\\\\y-(-5)=\dfrac{1}{11}(x-(-9))\\\\\boxed{y+5=\dfrac{1}{11}(x+9)}\leftarrow\boxed{\text{point-slope form}}

The standard form of a line:

Ax+By=C

y+5=\dfrac{1}{11}(x+9)                <em>multiply both sides by 11</em>

11y+55=1(x+9)

11y+55=x+9     <em>subtract 9 from both sides</em>

11y+46=x      <em>subtract 11y from both sides</em>

46=x-11y

\boxed{x-11y=46}\leftarrow\boxed{\text{standard form}}

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3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

D

Step-by-step explanation:

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