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3 years ago

Find the real solutions of the following equation. x^4 – x^2 + 4x^2 - 16x - 192 = 0

Mathematics

1 answer:

jenyasd209 [6]3 years ago

4 0

X=4 x=-3 x=-4.0 x=4.0

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Simplify (√3 − √7)^2

Alika [10]

Answer: 10 - 2√21

Step-by-step explanation: I simplified your question by using an online calculator. :)

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3 years ago

Why is it impossible to determine whether the equation 5x+10=25 is true / false ? Explain

Assoli18 [71]

You need to know the value of X to determine whether or not the equation is true.

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3 years ago

Read 2 more answers

Please help!!<br> im not sure how to find the answer

Sophie [7]

Answer:

Step-by-step explanation:

Add: 67+41+91+68=267

Subtract: 360-267=93

Hope this helps

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3 years ago

Morris has 2 3/4 gallons of ice tea. He gives 3/7 of it to her friend. How many gallons of ice tea does Morris have left?

lara31 [8.8K]

Answer:

$2 \frac{9}{28}$ gallons of ice tea is left with Morris

Step-by-step explanation:

Morris has 2 3/4 gallons of ice tea. He gives 3/7 of it to her friend.

Morris has 2 3/4 gallons of ice tea

$2\frac{3}{4}= \frac{2*4+3}{4}=\frac{11}{4}$

He gives 3/7 of it to her friend.

To find how many gallons of ice tea does Morris have left , we subtract 3/7 from 11/4

$\frac{11}{4}- \frac{3}{7}$

Make the denominators same

$\frac{11*7}{4*7}- \frac{3*4}{7*4}$

$\frac{77}{28}- \frac{12}{28}$

$\frac{65}{28}$

$\frac{65}{28} = 2 \frac{9}{28}$

7 0

2 years ago

Newton’s law of cooling states that dx/dt= −k(x − A) where x is the temperature, t is time, A is the ambient temperature, and k

Vadim26 [7]

Answer:

(a) The solution to the differential equation is x = A_0Coswt + Ce^(-kx)

(b) The initial condition t > 0 will not make much of a difference.

Step-by-step explanation:

Given the differential equation

dx/dt= −k(x − A); t > 0, A = A_0Coswt

(a) To solve the differential equation, first separate the variables.

dx/(x - A) = -kdt

Integrating both sides, we have

ln(x - A) = -kt + c

x - A = Ce^(-kt) (Where C = ce^(-kt))

x = A + Ce^(-kx)

Now, we put A = A_0Coswt

x = A_0Coswt + Ce^(-kx) (Where C is constant.)

And we have the solution.

(b) Since temperature t ≠ 0, the initial condition t > 0 will not make much of a difference because, Cos(wt) = Cos(-wt).

It is not any different from when t < 0.

7 0

2 years ago