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2 years ago

(math and social studies) The two lines are messing me up and I'm not sure

Mathematics

1 answer:

Ludmilka [50]2 years ago

8 0

Answer:

2009

Step-by-step explanation:

A deficit would be the least amount coming in (Revenues). and the most going out (Expenditures). So you look for the biggest gap. It appears the gap is largest in 2009.

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Marisol has 5 times as many books as jerry. Jerry has 15 books. How many more books does marisol have

ICE Princess25 [194]

Answer:

5 times more books

Step-by-step explanation:

In total Marisol has 75 books. She has 5 times as many books and Jerry has 15. 5*15=75

6 0

1 year ago

-3/5x - 7/20x + 1/4x= -56

romanna [79]

Answer:

x = 80

Step-by-step explanation:

Combine − 3/5x and 7/20x to get -19/20x.

Then combine -19/20x and 1/4x and you get -7/10x.

Then you multiply both sides by -10/7 which is the reciprocal of -7/10.

Make -56(-10) one fraction.

Multiply -56 and -10 and you get 560.

Then divide 560 by 7 to get 80.

8 0

3 years ago

Read 2 more answers

A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is

koban [17]

The expected length of code for one encoded symbol is

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha$

where $p_\alpha$ is the probability of picking the letter $\alpha$ , and $\ell_\alpha$ is the length of code needed to encode $\alpha$ . $p_\alpha$ is given to us, and we have

$\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}$

so that we expect a contribution of

$\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375$

bits to the code per encoded letter. For a string of length $n$ , we would then expect $E[L]=1.375n$ .

By definition of variance, we have

$\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2$

For a string consisting of one letter, we have

$\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4$

so that the variance for the length such a string is

$\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859$

"squared" bits per encoded letter. For a string of length $n$ , we would get $\mathrm{Var}[L]=1.859n$ .

5 0

2 years ago

In the expression 3x-10 which would be the constant

ArbitrLikvidat [17]

Answer:

-10

Step-by-step explanation:

The constant is the part of the algebraic function or expression that does not change. In this case, as x changes, the constant -10 does not. Thus, -10 is the constant.

4 0

2 years ago

Lynn plotted point G, 3 units to the left and 2 units above point F. Where did lynn plot point G?

kvasek [131]

Answer:

$G = (2,6)$