Which one is the one you want, 781:-:(divison)26?
Sin2(x) +cos(x)=1
from the relation: (sin2(x) +cos2(x) =1 )
so , sin2(x)=1-cos2(x)
by subs. in the main eqn.
1-cos2(x) + cos(x) =1
by simplify the eqn.
cos(x) -cos2(x)=0
take cos(x) as a common factor
cos(x)* (1-cos(x))=0
then cos(x)=0 && cos(x)=1
cos(x)=0 if x= pi/2
& cos(x) = 1 if x = 0 , 2*pi
so the solution is x= {0,pi/2 , 2*pi}
For this case, the first thing we must take into account is the following definition:
d = v * t
Where,
d: distance
v: speed
t: time
Substituting values we have:
Trip 1:
50 = v * t1
We cleared t1:
t2 = (50) * (1 / v)
Trip 2:
300 = (3 * v) * t2
We cleared t2:
t2 = (300/3) * (1 / v)
t2 = (100) * (1 / v)
Rewriting:
t2 = 2 (50) * (1 / v)
t2 = 2 * t1
Answer:
His new time compared with the old time was:
Twice the old time.
t2 = 2 * t1.
Answer:
The domain is the number of gallons and the range is the distance traveled.
Since the car can travel 30 miles one gallon of gas, we multiply by 12 to get the distance the car can travel in 12 gallons of gas.
