We are given the following functions

Let us first find f(g(x)
Substitute x = 5x - 1 into the function f(x) and simplify

Now let us find g(f(x))
Substitute x = x² - 3x + 1 into the function g(x) and simplify

Therefore, f(g(x) and g(f(x)) are
I'm assuming a 5-card hand being dealt from a standard 52-card deck, and that there are no wild cards.
A full house is made up of a 3-of-a-kind and a 2-pair, both of different values since a 5-of-a-kind is impossible without wild cards.
Suppose we fix both card values, say aces and 2s. We get a full house if we are dealt 2 aces and 3 2s, or 3 aces and 2 2s.
The number of ways of drawing 2 aces and 3 2s is

and the number of ways of drawing 3 aces and 2 2s is the same,

so that for any two card values involved, there are 2*24 = 48 ways of getting a full house.
Now, count how many ways there are of doing this for any two choices of card value. Of 13 possible values, we are picking 2, so the total number of ways of getting a full house for any 2 values is

The total number of hands that can be drawn is

Then the probability of getting a full house is

Answer: 5 * 23 = 115 so 40<
Step-by-step explanation:
Answer:
Allan can order them from least to greatest.
Step-by-step explanation:
The answer is diameter: 32 in, area: 64 in²
The perimeter of a sector of a circle is:
P = 2r + l
l = r<span>θ
P = 2r + r</span>θ<span>
P = 32 in
32 = 2r + r</span><span>θ
</span>32 - 2r = r<span>θ
</span>θ = (32 - 2r)/r
θ = (2*16 - 2*r)/r
θ = 2(16 - r)/r<span>
Area of the sector of the circle is:
A = r</span>²/2 * θ
A = r²/2 * 2(16 - r)/r
A = r² * (16 - r)/r
A = r(16 - r)
A = 16r - r²
For the maximum area:
A' = 16 - 2r
A' = 0
16 - 2r = 0
16 = 2r
r = 8 in
The diameter (D) of the circle is twice of the radius:
D = 2r = 2 * 8 = 16 in
The maximum area is:
A = 16r - r²
r = 8 in
A = 16 * 8 - 8²
A = 128 - 64
A = 64 in²