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Leno4ka [110]
3 years ago
8

How much tax is withheld from 53,620 if tax rate is 7%.?

Mathematics
2 answers:
Anna [14]3 years ago
5 0

3753.40 becuase .07 is 7% multiply it  by 53620 and you get 3753.40


Tems11 [23]3 years ago
3 0

The withheld tax is 3753.4

To get this you do 53,620 x .07

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Find f(g(x)) and g(f(x)) 1. F(x) = X²-3x+1 g(x)=5x-7
Mariana [72]

We are given the following functions

\begin{gathered} f(x)=x^2-3x+1 \\ g(x)=5x-7 \end{gathered}

Let us first find f(g(x)

Substitute x = 5x - 1 into the function f(x) and simplify

\begin{gathered} f(g(x))=(5x-7)^2-3(5x-7)+1 \\ f(g(x))=(25x^2-2\cdot5x\cdot7+49)^{}-15x+21+1 \\ f(g(x))=25x^2-70x+49^{}-15x+22 \\ f(g(x))=25x^2-70x-15x+49+22 \\ f(g(x))=25x^2-85x+71 \end{gathered}

Now let us find g(f(x))

Substitute x = x² - 3x + 1 into the function g(x) and simplify

\begin{gathered} g(f(x))=5(x^2-3x+1)-7 \\ g(f(x))=5x^2-15x+5-7 \\ g(f(x))=5x^2-15x-2 \end{gathered}

Therefore, f(g(x) and g(f(x)) are

\begin{gathered} f(g(x))=25x^2-85x+71 \\ g(f(x))=5x^2-15x-2 \end{gathered}

5 0
1 year ago
Find the probability of being dealt a full house. (Round your answer to six decimal places.)?
vesna_86 [32]

I'm assuming a 5-card hand being dealt from a standard 52-card deck, and that there are no wild cards.

A full house is made up of a 3-of-a-kind and a 2-pair, both of different values since a 5-of-a-kind is impossible without wild cards.

Suppose we fix both card values, say aces and 2s. We get a full house if we are dealt 2 aces and 3 2s, or 3 aces and 2 2s.

The number of ways of drawing 2 aces and 3 2s is

\dbinom42\dbinom43=24

and the number of ways of drawing 3 aces and 2 2s is the same,

\dbinom43\dbinom42=24

so that for any two card values involved, there are 2*24 = 48 ways of getting a full house.

Now, count how many ways there are of doing this for any two choices of card value. Of 13 possible values, we are picking 2, so the total number of ways of getting a full house for any 2 values is

2\dbinom{13}2\dbinom42\dbinom43=3744

The total number of hands that can be drawn is

\dbinom{52}5=2,598,960

Then the probability of getting a full house is

\dfrac{2\binom{13}2\binom42\binom43}{\binom{52}5}=\dfrac6{4165}\approx\boxed{0.001441}

4 0
3 years ago
Find the value of 5 ∙ 23.<br><br><br>30<br><br>40&lt;<br><br>1,000
Mashutka [201]

Answer:  5 * 23 = 115 so 40<

Step-by-step explanation:

4 0
3 years ago
Allan is ordering a set of rational numbers that includes positive values, negative values , fractions , and decimal numbers . H
anastassius [24]

Answer:

Allan can order them from least to greatest.

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
Suppose you are offered just one slice from a round pizza (in other words, a sector of a circle). The slice must have a perimete
schepotkina [342]
The answer is diameter: 32 in, area: 64 in²

The perimeter of a sector of a circle is:
P = 2r + l
l = r<span>θ
P = 2r + r</span>θ<span>

P = 32 in
32 = 2r + r</span><span>θ
</span>32 - 2r = r<span>θ
</span>θ = (32 - 2r)/r
θ = (2*16 - 2*r)/r
θ = 2(16 - r)/r<span>

Area of the sector of the circle is:
A = r</span>²/2 * θ
A = r²/2 * 2(16 - r)/r
A = r² * (16 - r)/r
A = r(16 - r)
A = 16r - r²

For the maximum area:
A' = 16 - 2r
A' = 0
16 - 2r = 0
16 = 2r
r = 8 in

The diameter (D) of the circle is twice of the radius:
D = 2r = 2 * 8 = 16 in

The maximum area is:
A = 16r - r²
r = 8 in
A = 16 * 8 - 8²
A = 128 - 64
A = 64 in²
7 0
3 years ago
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