We can rewrite the expression under the radical as

then taking the fourth root, we get
![\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cleft%28%5Cdfrac32a%5E2b%5E3c%5E4%5Cright%29%5E4%7D%3D%5Cleft%7C%5Cdfrac32a%5E2b%5E3c%5E4%5Cright%7C)
Why the absolute value? It's for the same reason that

since both
and
return the same number
, and
captures both possibilities. From here, we have

The absolute values disappear on all but the
term because all of
,
and
are positive, while
could potentially be negative. So we end up with

Answer= $185.00
Commission=15(10)+2(17.50)
Commission=150+35.00
Commission=$185.00
It depend on where you are working at that isn't a specific question
True. 5/8 + 1/2 is. 9/8. Yes he have trained enough, even more than a mile