Answer:
x₂ = 7.9156
Step-by-step explanation:
Given the function ln(x)=10-x with initial value x₀ = 9, we are to find the second approximation value x₂ using the Newton's method. According to Newtons method xₙ₊₁ = xₙ - f(xₙ)/f'(xₙ)
If f(x) = ln(x)+x-10
f'(x) = 1/x + 1
f(9) = ln9+9-10
f(9) = ln9- 1
f(9) = 2.1972 - 1
f(9) = 1.1972
f'(9) = 1/9 + 1
f'(9) = 10/9
f'(9) = 1.1111
x₁ = x₀ - f(x₀)/f'(x₀)
x₁ = 9 - 1.1972/1.1111
x₁ = 9 - 1.0775
x₁ = 7.9225
x₂ = x₁ - f(x₁)/f'(x₁)
x₂ = 7.9225 - f(7.9225)/f'(7.9225)
f(7.9225) = ln7.9225 + 7.9225 -10
f(7.9225) = 2.0697 + 7.9225 -10
f(7.9225) = 0.0078
f'(7.9225) = 1/7.9225 + 1
f'(7.9225) = 0.1262+1
f'(7.9225) = 1.1262
x₂ = 7.9225 - 0.0078/1.1262
x₂ = 7.9225 - 0.006926
x₂ = 7.9156
<em>Hence the approximate value of x₂ is 7.9156</em>
Answer:
incorrect length is 12.5
actual length is 11
12.5-11
1.5
1.5/12.5 ×100
20%
Step-by-step explanation:
hope it helps
Answer:
1050, 1200, 2550 and 5100.
Step-by-step explanation:
If the first number is x then the second is x + 1/7x.
The third = x + x + 1/7x + 300 and the fourth = x + x + 1/7x + x + x + 1/7x+ 300 + 300.
So our equation is:-
8x + 4 * 1/7x + 900 = 9900
60/7 = 9000
60x = 7*9000
x = 1050.
Therefore the 4 numbers are 1050, *1/7*1050 = 1200, 2550 and 5100.
The slope would be 0. hope this is helpful!
